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我能够从Android程序向远程服务器发送请求,但似乎请求没有参数。我如何附加参数?如何将请求参数附加到当前Android HttpUrlConnection调用
这里是我当前的代码:
@Override
protected String doInBackground(String... theParams)
{
String myUrl = theParams[0];
final String myEmail = theParams[1];
final String myPassword = theParams[2];
Authenticator.setDefault(new Authenticator()
{
protected PasswordAuthentication getPasswordAuthentication()
{
return new PasswordAuthentication(myEmail, myPassword.toCharArray());
}
});
String response = null;
try
{
final URL url = new URL(myUrl);
final HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestProperty("login", myEmail);
conn.setRequestProperty("password", myPassword);
conn.setUseCaches(false);
final InputStream is = conn.getInputStream();
final byte[] buffer = new byte[8196];
int readCount;
final StringBuilder builder = new StringBuilder();
while ((readCount = is.read(buffer)) > -1)
{
builder.append(new String(buffer, 0, readCount));
}
response = builder.toString();
Log.d("After call, response: " , " " + response);
}
catch (Exception e)
{
}
return response;
}
所以,现在我不知道如何进行身份验证的密码/登入得到重视的请求,并会发送到服务器。任何想法我怎么能做到这一点?
谢谢!
@Nikil但这不是一个安全缺陷?不应该隐藏密码吗?我没有在我的情况下使用https。谢谢! – Genadinik 2012-02-28 20:59:50
这是一个不同的问题。除非您有加密/解密逻辑或通过SSL进行通信,否则传递的凭据将始终以纯文本格式显示。 – Nikhil 2012-02-29 04:48:34
@NikhilPatil,你好我想谈谈你有关在Android中添加参数到POST请求的问题 – 2015-04-14 11:35:23