2010-11-09 118 views
12

我试图将“大于”where语句转换为CI的活动记录语法。当我使用这个片段Codeigniter活动记录:大于语句

$this->db->join('product_stocks', "product_stocks.size_id_fk = product_attributes.id", "left"); 
    $this->db->where('product_stocks.stock_level', '> 1');  
    $result = $this->db->get('product_attributes')->result_array(); 

然后打印$这个 - > DB-> last_query();显示WHERE product_stocks . stock_level = '> 1'这当然是不正确的。这可以做到吗?

回答

52

我想这应该做的伎俩:

$this->db->where('product_stocks.stock_level >', '1'); //moved the > 
0

我想在CI如下:

$sQuery = "SELECT auftrag, saal, DATE_FORMAT(konzertdatum,'%e, %M, %Y') AS konzertdatum2 FROM auftrag 
    JOIN saal on auftrag.saal_id = saal.id 
    WHERE konzertdatum < NOW() + INTERVAL 240 DAY AND auftrag like '%$sWord%' order by konzertdatum asc LIMIT 4"; 
$aOrder = $this->db->query($sQuery); 
$aOrder = $aOrder->result(); 

它工作正常,没有CI,但是当我使用

 $this->db->select("auftrag, saal, DATE_FORMAT(konzertdatum,'%e, %M, %Y') AS konzertdatum2", false); 
    $this->db->from('auftrag'); 
    $this->db->join('saal', 'auftrag.saal_id = saal.id'); 
    $this->db->like('auftrag', $sWord); 
    $this->db->where('konzertdatum <', 'NOW() + Interval 240 day'); 

    $this->db->order_by('konzertdatum'); 
    $this->db->limit(4); 

    $oQuery = $this->db->get(); 

    $aOrder = $oQuery->result(); 
    print_r($this->db->last_query()); 

它返回所有结果不关心的地方(虽然SQL似乎很好):

SELECT auftrag, saal, DATE_FORMAT(konzertdatum, '%e, %M, %Y') AS konzertdatum2 FROM (`auftrag`) JOIN `saal` ON `auftrag`.`saal_id` = `saal`.`id` WHERE `konzertdatum` < 'NOW() + Interval 240 day' AND `auftrag` LIKE '%spangenberg%' ORDER BY `konzertdatum` LIMIT 4 
2

你也可以传递一个字符串参数,像这样的地方()函数,

$this->db->where('product_stocks.stock_level > 1'); 
4

无论是

$this->db->where('product_stocks.stock_level >', '1');
$this->db->where(array('product_stocks.stock_level >'=>'1'));
应该这样做。请注意字段名称和操作员之间的空白处;否则你最终会得到错误1064.

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