如何在Android的IntentService中获取用户的当前位置？

这就是我想要做的。我有主要Activity调用BroadcastReceiver名称SmsAlarmReceiver。如何在Android的IntentService中获取用户的当前位置？

Intent i = new Intent(SmsAlarmReceiver.ALARM_ACTION); 
sendBroadcast(i);

现在我SmsAlarmReceiver.java样子：

public class SmsAlarmReceiver extends BroadcastReceiver { 

LocationManager locationmanager; 
public static final String ALARM_ACTION= "com.example.finaltracking.SMS_REC"; 
@TargetApi(Build.VERSION_CODES.GINGERBREAD) 
@Override 
public void onReceive(Context context, Intent intent) { 
    // TODO Auto-generated method stub 
    locationmanager = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE); 
    Intent smsintent = new Intent(context,SmsService.class); 
    PendingIntent pendingintent = PendingIntent.getService(context, 0, smsintent, 0); 
    locationmanager.requestLocationUpdates(LocationManager.GPS_PROVIDER,1*60*1000,10,pendingintent); 
}

}

所以在这种接收器，我请求使用的PendingIntent听位置改变位置更新。

我叫SmsService.java服务看起来像：

public class SmsService extends IntentService { 

public SmsService(String name) { 
    super(name); 
    // TODO Auto-generated constructor stub 
} 

@Override 
protected void onHandleIntent(Intent intent) { 
    // TODO Auto-generated method stub 
    Bundle bundle = intent.getExtras(); 
    Location location = (Location) bundle.get(LocationManager.KEY_LOCATION_CHANGED); 
    Log.d("msg", "Loc is " + location.getLatitude() +","+ location.getLongitude()); 
    sendMessage("983******","msg is " + location.getLatitude()+"," +location.getLongitude()); 
} 

private void sendMessage(String rec,String msg){ 

    //PendingIntent intent = PendingIntent.getActivity(this,0,new Intent(this,MainActivity.class),0); 
    SmsManager sms = SmsManager.getDefault(); 
    //Toast.makeText(getApplicationContext(),msg,Toast.LENGTH_LONG).show(); 
    ArrayList<String> parts = sms.divideMessage(msg); 
    sms.sendMultipartTextMessage(rec,null, parts,null, null); 
} 


    }

我的应用程序不强制关闭，但它不能发送到接收器指定的消息。

有没有更好的替代这个问题。简而言之，我想实现每5分钟发送一次用户GPS位置的功能，一旦用户启用了跟踪功能。我可以如何使用服务/意图服务/广播接收器来实现此功能。？请帮助..

来源

2013-10-17 Droidwala