我正在开发注册操作,其中用户输入他的电子邮件和密码按提交(createUser方法)按钮,用户实体得到持久并设置用户在HttpSession中的ID,接下来他转到下一个jsf,在那里输入学校对象(实体)的信息。我的问题是,用户得到坚持,但学校不是。这里是我的代码:为HttpSession设置属性后,它变为空
public CreateBn() {
user = new User();
school = new School();
adress = new Adresse();
school.setAdresse(adress);
facesContext = FacesContext.getCurrentInstance();
session = (HttpSession) facesContext.getExternalContext().getSession(false);
}
public String createUser() {
initialiserDateInscription();
session.setAttribute("UserId", user.getId());
//System.out.println((BigInteger) session.getAttribute("UserId"));
userPr.createUser(user);
return SHCOOL_INSCRIPTION;
}
public String createSchool() {
BigInteger userId = (BigInteger) session.getAttribute("UserId");
System.out.println("MEHDI : " + userId);
try {
User userTemp = userPr.getUserById(userId);// Here is the problem
school.setUser(userTemp);
} catch (Exception e) {
e.printStackTrace();
}
session.setAttribute("SchoolId", school.getId());
school.setAdresse(adress);
schoolPr.createSchool(school);
return INSCRIPTION_RETURN;
}
,你可以看到,我得到了用户实体基于保存在会话中的用户ID,但我什么也没有,它说:
javax.persistence.NoResultException: getSingleResult() did not retrieve any entities.
任何更多的信息,我在这里。那么我该如何解决这个问题呢?
@Entity
@Table(schema = "school", name = "school")
public class School implements Serializable {
private static final long serialVersionUID = 1L;
@Id
private BigInteger id;
private String name;
@OneToOne(fetch=FetchType.EAGER)
@JoinColumn(name = "userId")
private User user;
@OneToOne(fetch=FetchType.LAZY, cascade=CascadeType.PERSIST)
@JoinColumn(name = "adressId")
private Adresse adresse;
EJB
@Stateless
public class UserPr {
@PersistenceContext(unitName = "proj")
private EntityManager em;
public void createUser(User user) throws RuntimeException{
try {
em.persist(user);
} catch (Exception e) {
throw new RuntimeException(e);
}
}
public User getUserById(BigInteger UserId) throws Exception{
try{
return em.createNamedQuery("User.findById", User.class).setParameter("id", UserId).getSingleResult();
}catch(Exception e){
e.printStackTrace();
}
return null;
}
}
@NamedQueries({
@NamedQuery(name="User.findById", query="SELECT u FROM User u WHERE u.id = :id")
})
public class User implements Serializable {
你可以发布userPr类的代码吗? – 2014-09-22 10:01:42
另外,正如我在您发布的代码中所看到的那样,当您调用createUser函数时,您不会在用户对象中设置任何内容。即你不呼叫某处user.id = id。也许,你在我看不到的部分代码中实现了这一点。在数据库中,用户对象是否正确保存? – 2014-09-22 10:06:45
用户得到坚持在DB中,我看到表更改。问题在于设置UserId并从会话中获取。 enity用户在构造函数中初始化,所以我只需要持久 – user3923327 2014-09-22 10:07:38