如何从data.tree对象获取节点的深度？

Question

比方说，我有一个这样的测试数据：

library(data.tree) 

df <- structure(list(parent = c("part1", "part3", "part7", "part4", 
"part9", "part1"), child = c("part7", "part12", "part4", "part27", 
"part10", "part13"), children = c("part4", "", "part27", "", 
"", ""), children1 = c("part27", "", "", "", "", ""), pathString = c("Root/part1/part7/part4/part27", 
"Root/part3/part12//", "Root/part7/part4/part27/", "Root/part4/part27//", 
"Root/part9/part10//", "Root/part1/part13//")), .Names = c("parent", 
"child", "children", "children1", "pathString"), row.names = c(NA, 
6L), class = "data.frame") 
df$children <- "" 
df$children1 <- "" 

我创建了一个data.tree如下：

test_tree <- as.Node(df) 
print(test_tree, limit = 50) 

我试图让每一父节点的深度树从根。 尝试阅读文档，但我找不到与树的深度有关的任何内容。

R有没有一种方法从这个data.tree图中获取树的深度？

Answer 1

不确定你的意思是'根中树中每个父节点的深度'。也许这个？

library(data.tree) 
data(acme) 
print(acme, 'height', 'level') 

这将打印这样的：

      levelName height level 
1 Acme Inc.        3  1 
2 ¦--Accounting      2  2 
3 ¦ ¦--New Software     1  3 
4 ¦ °--New Accounting Standards  1  3 
5 ¦--Research       2  2 
6 ¦ ¦--New Product Line    1  3 
7 ¦ °--New Labs      1  3 
8 °--IT        2  2 
9  ¦--Outsource      1  3 
10  ¦--Go agile      1  3 
11  °--Switch to R     1  3 

注意height和level上Node性能/活性。所以你也可以拨打acme$height。 有关所有活动的列表，请键入?Node。