我在javascript调用中创建了一个表格,并通过页面上的iframe显示数据链接被选中。我试图在用户悬停在一行上时突出显示一个表格行。我向表中添加了一个类,然后添加了后续的css代码,但是我在表中显示的行上得到了一个解析错误。有关如何清除它的任何想法?突出显示鼠标悬停时的表格行
<!DOCTYPE HTML>
<html lang = "en">
<head>
<link rel="stylesheet" type="text/css" href="mystylesheet.css">
<title>Tech Order Department.html</title>
<meta charset = "UTF-8" />
</head>
<body>
<h2>Completed Projects</h2>
<br>
<?php
$servername = "localhost";
$username = "xxx";
$password = "xxx";
$dbname = "xxx";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
//Set up and run my Query
$sql = "SELECT Project, Client, DateReceived, LastName, FinalReviewDate, DateDelivered, DateAccepted FROM Projects
WHERE DateAccepted IS NOT NULL
ORDER BY DateAccepted DESC";
$result = $conn->query($sql);
//Display results
if ($result->num_rows > 0) {
echo "<table class="hoverTable"><tr><th>Client</th><th>Project</th><th>Point of Contact</th><th>Date Project Received</th><th>Final Review Date</th><th>Date Delivered</th><th>Date Accepted</th></tr>";
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<tr><td>" . $row["Client"]. "</td><td>" . $row["Project"]. "</td><td> " . $row["LastName"]. "</td><td> " . $row["DateReceived"]. "</td><td> " . $row["FinalReviewDate"]. "</td><td> " . $row["DateDelivered"]. "</td><td> " . $row["DateAccepted"]. "</td></tr>";
}
echo "</table>";
} else {
echo "0 results";
}
$conn->close();
?>
</body>
</html>
也许是这样的:http://stackoverflow.com/a/5492951/636676 – Freddy
您可以在你的问题你的'css'?谢谢。 – Rounin
@Freddi我不认为这些涉及通过javascript创建表。 CSS不是问题。如果它不解析,CSS将无关紧要。 – Tony