我需要从URL调用Web服务。我在文本框中输入了no,我应该输入文本框中输入的内容。请帮我修复错误。这里是我的java代码。如何在Android中调用Web服务
MainActivity.java
public class MainActivity extends Activity {
Button b;
TextView tv;
EditText et;
String editText;
String displayText;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
et = (EditText) findViewById(R.id.editText1);
tv = (TextView) findViewById(R.id.tv_result);
b = (Button) findViewById(R.id.button1);
b.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
if (et.getText().length() != 0 && et.getText().toString() != "") {
editText = et.getText().toString();
AsyncCallWS task = new AsyncCallWS();
task.execute();
} else {
tv.setText("Please enter number");
}
}
});
}
private class AsyncCallWS extends AsyncTask<String, Void, Void> {
@Override
protected Void doInBackground(String... params) {
displayText = ser.invokeiop(editText,"hello");
return null;
}
}
}
ser.java
public class ser {
private static String NAMESPACE = "http://tempuri.org/";
private static String URL = "http://my url";
private static String SOAP_ACTION = "srvice";
public static String invokeiop(String name, String webMethName) {
String resTxt = null;
SoapObject request = new SoapObject(NAMESPACE, webMethName);
PropertyInfo iop = new PropertyInfo();
iop.setName("name");
iop.setValue(name);
//iop.setType(String.class);
request.addProperty(iop);
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
SoapEnvelope.VER11);
envelope.setOutputSoapObject(request);
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
try {
androidHttpTransport.call(SOAP_ACTION+webMethName, envelope);
SoapPrimitive response = (SoapPrimitive) envelope.getResponse();
resTxt = response.toString();
} catch (Exception e) {
e.printStackTrace();
resTxt = "Error occured";
}
你想说什么?你需要在Web服务中传递价值,并想要获取或其他? –
是的..请帮助。我是Android新手。 dnt knw怎么办 – user2603611
必须在web服务中传递值,我应该从中取值 – user2603611