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下面的代码的工作,但结果是空,是谁帮我找问题,似乎还有问题转换成字符串中的最终结果如何转换字符串中的存储过程来诠释
DECLARE @dp1 varchar
DECLARE @dp2 varchar
DECLARE @dp3 varchar
DECLARE @dp4 varchar
DECLARE @dpp1 int
DECLARE @dpp2 int
DECLARE @dpp3 int
DECLARE @dpp4 int
set @dp1 = 'Emkanat'
set @dp2 = 'Masraf'
if (@dp1= 'Emkanat')
Begin
set @dpp1= 8
Select Emkanat*@dpp1 as val1 FROM Cardetail
End
if (@dp1= 'Tarahi')
Begin
set @dpp1= 8
Select Tarahi*@dpp1 as val1 FROM Cardetail
End
if (@dp1= 'Sandogh')
Begin
set @dpp1= 8
Select Sandogh*@dpp1 as val1 FROM Cardetail
End
if (@dp1= 'Masraf')
Begin
set @dpp1= 8
Select Masraf*@dpp1 as val1 FROM Cardetail
End
if (@dp2= 'Emkanat')
Begin
set @dpp2= 7
Select Emkanat*@dpp2 as val2 FROM Cardetail
End
if (@dp2= 'Tarahi')
Begin
set @dpp2= 7
Select Tarahi*@dpp2 as val2 FROM Cardetail
End
if (@dp2= 'Sandogh')
Begin
set @dpp2= 7
Select Sandogh*@dpp2 as val2 FROM Cardetail
End
if (@dp2= 'Masraf')
Begin
set @dpp2= 7
Select Masraf*@dpp2 as val1 FROM Cardetail
End
SELECT
Namecar,
(Masraf*@dpp1)+(Sandogh*@dpp1)+(Tarahi*@dpp1)+(Emkanat*@dpp1)+(Masraf*@dpp2)+(Sandogh*@dpp2)+(Tarahi*@dpp2)+(Emkanat*@dpp2)
as finalresult
FROM Cardetail
为int变量需要由varchar提供,然后根据字符获取int
请更好地解释你的目标 –