2015-10-16 60 views
1

为什么我会收到两位来电号码?随着传出的细节它正常工作,但它只获得一次,但我不知道传入的细节会发生什么。谁能帮我?广播接收器来电(获取两倍来电号码)

public void onReceive(Context context, Intent intent) { 

    Log.d("APP", "ACTION:" + intent.getAction()); 
    //this.context = context; 
    final String stringExtra = intent.getStringExtra(TelephonyManager.EXTRA_STATE); 

    if (Intent.ACTION_NEW_OUTGOING_CALL.equals(intent.getAction())){ 
     //outgoing call 
     number=intent.getStringExtra(Intent.EXTRA_PHONE_NUMBER); 
     Log.i("tag", "Outgoing number : " +number); 
     currentDateTimeString = DateFormat.getDateTimeInstance().format(new Date()); 
     Log.i("tag", "Date :" + currentDateTimeString); 
     //doSaveCallRecord(1); 
     Log.i("tag", "USER ID :" + context.getSharedPreferences("APPLICATION",Context.MODE_PRIVATE).getString(UserConstants.ID,null)+""); 
    } 
    if (TelephonyManager.EXTRA_STATE_RINGING.equals(stringExtra)) { 
     final String incomingNumber = intent.getStringExtra(TelephonyManager.EXTRA_INCOMING_NUMBER); 
     Log.d("APP", "incoming,ringing:" + incomingNumber); 
     //doSaveCallRecord(0); 
    } 
} 
<receiver android:name=".MyCallReceiver" > 
     <intent-filter> 
      <action android:name="android.intent.action.NEW_OUTGOING_CALL"/> 
      <action android:name="android.intent.action.PHONE_STATE"/> 
     </intent-filter> 
</receiver> 
+0

请为sendBroadcast –

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提供代码请发表您的AndroidManifest为好,因为任何的logcat(即例如记录了一个呼叫)。最后,尝试描述一个重复所需和不想要的效果的示例条件。另外,所描述的事件可能是具有相同广播事件的两个或更多个接收器。在您登记的接收器(dinamically和静态地)显示 – Bonatti

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<接收机机器人: “MyCallReceiver” 名称=> <意图滤波器> <操作机器人:名称= “android.intent.action.NEW_OUTGOING_CALL”/> < action android:name =“android.intent.action.PHONE_STATE”/>

回答

0

这里是我的检查来电号码以特定数字代码:

@Override 
public void onReceive(final Context context, Intent intent) { 
    TelephonyManager telephony = (TelephonyManager)context.getSystemService(Context.TELEPHONY_SERVICE); 
    telephony.listen(new PhoneStateListener() { 
     @Override 
     public void onCallStateChanged(int state, String incomingNumber) { 
      super.onCallStateChanged(state, incomingNumber); 
      if(incomingNumber.contains("CHECKING NUMBER")){ 
       AudioManager audio_mngr = (AudioManager) context.getSystemService(Context.AUDIO_SERVICE); 
       audio_mngr.setRingerMode(AudioManager.RINGER_MODE_NORMAL); 
      } 
      System.out.println("incomingNumber : "+incomingNumber); 
     } 
    },PhoneStateListener.LISTEN_CALL_STATE); 
} 
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我们可以维护两个单独的广播接收器文件。一个用于拨出电话,另一个用于来电? –

+0

我仍然收到不超过两次 –