我正在使用工厂模式创建使用ElevatorMover
接口的不同类型的电梯。工厂将电梯存放在ElevatorMover
对象的ArrayList
中。当我从ArrayList
检索电梯[ElevatorArrayList.get(i)
]时,我无法拨打PassengerElevator
方法。只有ElevatorMover
方法(当然没有执行)。工厂模式/ ArrayList /接口问题
我在这里没有做什么?
这里是我试图在主
// make elevator 1 go to the 11th floor
testBuilding.getElevator(1).moveUp(11);
调用代码这是我的接口
public interface ElevatorMover {
public void moveUp(int i);
public void moveDown(int i);
public void openDoors();
这是PassengerElevator方法
@Override
public void moveUp(int i) {
while (currentFloor != i) {
setCurrentFloor(currentFloor++);
}
}
错误消息
Exception in thread "main" java.lang.NullPointerException
at Elevator.Building.getElevator(Building.java:109)
at Elevator.ElevatorSimulatorMain.main(ElevatorSimulatorMain.java:34)
个
Building.class构造
private ArrayList<Floor> floorArrayList; // the ArrayList of floors in the building
private ArrayList<ElevatorMover> elevatorArrayList; // the ArrayList of elevators in the building
public Building(int numFloors, int numElevators) {
this.numFloors = numFloors;
this.numElevators = numElevators;
// create each floor
if (numFloors > 0) // Must have 1 or more floors
{
for (int i = 1; i <= numFloors; i++) {
floorArrayList.add(new Floor(i));
}
}
else
{
System.out.println("Building must have 1 or more floors.");
}
// create each elevator.
if (numElevators > 0) // Must have 1 or more elevators
{
for (int i = 1; i <= numElevators; i++) {
elevatorArrayList.add(ElevatorFactory.build("Passenger", i));
}
}
else
{
System.out.println("Building must have 1 or more elevators.");
}
}
ElevatorFactory构建方法
public static ElevatorMover build(String type, int elevID) {
if (type.equals("Passenger")) {
return new PassengerElevator(elevID);
}
else return null; // don't know what this is
}
的getElevator方法
public ElevatorMover getElevator(int i) {
return elevatorArrayList.get(i);
}
代码段请。 – Kode 2015-02-10 01:50:25
为什么您认为PassengerElevator方法在该方法可能返回ElevatorMover时应该可用? – 2015-02-10 01:52:23
@AmirAfghani也许我误解了接口的功能,但我使用的接口是A)在不同类型的电梯之间提供通用方法,B)允许将我的各种类型的电梯分组到ArrayList中。 – clenard 2015-02-10 02:00:20