我使用SERDE和serde_json 1.0从一个base64字符串数据进行解码:终身错误创建一个返回值实现SERDE ::反序列化
fn from_base64_str<T: Deserialize>(string: &str) -> T {
let slice = decode_config(string, URL_SAFE).unwrap();
serde_json::from_slice(&slice).unwrap()
}
当我编译,我得到这个:
error[E0106]: missing lifetime specifier
--> src/main.rs:6:23
|
6 | fn from_base64_str<T: Deserialize>(string: &str) -> T {
| ^^^^^^^^^^^ expected lifetime parameter
检查SERDE DOC,Deserialize
被定义为:
pub trait Deserialize<'de>: Sized {
所以我一dded寿命:
fn from_base64_str<'de, T: Deserialize<'de>>(string: &str) -> T {
let slice = decode_config(string, URL_SAFE).unwrap();
serde_json::from_slice(&slice).unwrap()
}
编译器然后告诉我:
error: `slice` does not live long enough
--> src/main.rs:11:29
|
11 | serde_json::from_slice(&slice).unwrap()
| ^^^^^ does not live long enough
12 | }
| - borrowed value only lives until here
|
note: borrowed value must be valid for the lifetime 'de as defined on the body at 9:64...
--> src/main.rs:9:65
|
9 | fn from_base64_str<'de, T: Deserialize<'de>>(string: &str) -> T {
| _________________________________________________________________^ starting here...
10 | | let slice = decode_config(string, URL_SAFE).unwrap();
11 | | serde_json::from_slice(&slice).unwrap()
12 | | }
| |_^ ...ending here
我只知道在鲁斯特的寿命非常基本的,所以我非常受'de
在trait Deserialize
混淆。
我该如何解决这种功能中的生存期错误?我使用锈1.18.0-每晚(452bf0852 2017-04-19)