Ohkk这里是一个好主意,以及使用html.Action
,而不是html.partial
这看起来更像是这样的:
public ActionResult Dashboard()
{
return View();
}
public PartialViewResult Clubs()
{
....
return PartialView(db.Clubs.ToList());//this assumes the partial view is named Clubs.cshtml, otherwise you'll need to use the overload where you pass the view name
}
public PartialViewResult Alerts()
{
....
return PartialView(db.Alerts.ToList());
}
Dashboard.cshtml
<div class="dashboard_alerts">
@Html.Action("Alerts")
<div class="dashboard_pending_clubs">
@Html.Action("Clubs")
</div>
<div class="dashboard_verified_members">
@Html.Action("Members")
</div>
OR
您将需要创建一个视图模型特定的仪表盘页面正是这将是更有效的方式
public class DashboardViewModel
{
public IEnumerable<GMC.Models.Clubs> Clubs { get; set; }
public IEnumerable<GMC.Models.MemberUsers> Users { get; set; }
public IEnumerable<GMC.Models.Alerts> Alerts { get; set; }
}
然后,在仪表板的操作方法,你会填充每个列表:
myModel.Users = db.MemberUsers.ToList();
... 你会那么需要更新的观点在这方面采取新的视图模型
@model DashboardViewModel
最后,从视图中,您需要在数据传递给每个部分:
@Html.Partial("DashboardAlerts", Model.Alerts)
@Html.Partial("DashboardClubs", Model.Clubs)
谢谢!非常好的答案! – LifeOf0sAnd1s
很高兴它有助于快乐编码:) – Curiousdev