返回分数

Question

这是我的代码，它可以从多个成员中创建分组，然后对每个分组进行评分，然后对它们进行评分，以获得这种情况下4个分组的总分。

import random 

def run(members, n_groups): 
    participants = list(range(1,members+1))*n_groups 
    random.shuffle(participants) 

    my_groups = list(zip(*[iter(participants)]*members)) 
    print(my_groups) 

    def get_rating(group): 
     return (len(set(group))) 

    score = ((sum(get_rating(g) for g in my_groups))) 
    print(score) 
    return score 

members = 4 
n_groups = 4 

print(min(run(members, n_groups) for _ in range(10))) 

输出：

[(3, 3, 4, 1), (4, 2, 3, 1), (2, 3, 2, 4), (1, 1, 4, 2)] 
13 
[(3, 1, 1, 4), (2, 3, 2, 4), (1, 4, 1, 2), (3, 2, 4, 3)] 
12 
[(2, 4, 4, 1), (3, 3, 1, 3), (3, 1, 2, 2), (4, 4, 2, 1)] 
11 
[(3, 1, 4, 1), (3, 1, 2, 1), (2, 2, 4, 4), (3, 2, 3, 4)] 
11 
[(1, 1, 3, 1), (2, 2, 3, 1), (3, 2, 4, 4), (4, 4, 3, 2)] 
11 
[(3, 2, 1, 2), (4, 1, 3, 4), (4, 2, 3, 1), (1, 2, 4, 3)] 
14 
[(2, 4, 3, 1), (3, 4, 4, 2), (1, 1, 2, 1), (3, 3, 4, 2)] 
12 
[(3, 3, 1, 2), (2, 1, 3, 3), (2, 4, 4, 2), (4, 1, 1, 4)] 
10 
[(1, 4, 3, 2), (4, 2, 3, 3), (3, 1, 2, 1), (4, 4, 1, 2)] 
13 
[(2, 4, 1, 3), (3, 2, 2, 3), (1, 4, 1, 3), (1, 4, 2, 4)] 
12 
10 

所以每个组得到一个等级，然后最小分数显示在底部，有没有我可以重印得到了分钟得分后组的方法吗？因为如果我尝试了10万次，我很难检查每一个来找出它来自哪个组。

我想：

import random 

def run(my_groups, score): 
    participants = list(range(1,members+1))*n_groups 
    random.shuffle(participants) 

    my_groups = list(zip(*[iter(participants)]*members)) 
    print(my_groups) 

    def get_rating(group): 
     return (len(set(group))) 

    score = ((sum(get_rating(g) for g in my_groups))) 
    print(score) 
    return score 

members = 4 
n_groups = 4 

print(min(run(members, n_groups) for _ in range(10), key=lambda x:x[1])) 

但这种回报“发电机表达必须如果不是唯一的参数括号”，用于运行支架？

Answer 1

import random 


def run(members, n_groups): 
    participants = list(range(1, members + 1)) * n_groups 
    random.shuffle(participants) 

    my_groups = list(zip(*[iter(participants)] * members)) 
    return my_groups 


def get_rating(group): 
    return len(set(group)) 


def score(my_groups): 
    return sum(get_rating(g) for g in my_groups) 


best = min(*(run(4, 4) for _ in range(10)), 
      key=score) 
print(best) 
print(score(best)) 

Answer 2

更改run返回my_groups, score。

然后改变

min(run(members, n_groups) for _ in range(10)) 

到

min((run(members, n_groups) for _ in range(10)), key=lambda x:x[1]) 

这使得使得min返回整个(my_groups, score)元组，但只比较score（元组的第二元件）来找到最小值。