C++ ofstream没有写出来自结构数组的所有输入

Question

这是我第一次在大学里为C++课程，这是我的第二个项目。所以这个项目一直强调我，但是，项目几乎完成了。 我的流媒体代码有效，但它只是用上次输入的信息创建文件，而不是存储所有信息输入。此外，我知道我用来检查手机输入的位数的代码不起作用。我有一个想法做什么，但任何帮助表示赞赏。

#include <iostream> 
#include <string> 
#include <fstream> 
using namespace std; 



struct Contributor 
{ 
string firstName; 
string lastName; 
double amount; 
string number; 
string class_con; 
}; 
//Prototype************************ 
void input(); 
void display(); 
//********************************* 

//Global Variable****************** 
Contributor*contributors = NULL; 
int count; 
//********************************* 

//Program will run here************ 
int main() 
{ 
    input(); 
    display(); 
} 
//********************************* 

//Functions to be prototype******** 
void input() 
{ 

cout << "Enter the number of Contributors" << endl; 
cin >> ::count; 

contributors = new Contributor[::count]; 

for (int i = 0; i < ::count; i++) 
{ 
    bool amount_correct = false; bool phone_correct = false; 
    //Name Member 
    cout << "First Name and Last Name of contributor" << endl; 
    cin >> contributors[i].firstName >> contributors[i].lastName; 
    //Amount Member 
    double amount; 
    cout << "Enter the amount[amount>500 && amount<20000]" << endl; 
    cin >> amount; 
    while (!amount_correct) 
    { 
     if (amount >= 500 && amount <= 20000) 
     { 
      contributors[i].amount = amount; 
      amount_correct = true; 
     } 
     else 
     { 
      cout << "Invalid amount!! Please re-enter a value that is greater than 500, and less than 20000: " << endl; 
      cin >> amount; 
     } 
    } 
    {//phone member 
     string phone; 
     cout << "Enter phone number: "; 
     cin >> phone; 
     while (!phone_correct) 
     { 
      bool flag = false; 
      for (int j = 0; j < (phone.length() - 1); j++) 
      { 
       if (!((int)phone[j] < 10)) 
       { 
        flag = true; 
       } 
      } 
      if (flag) 
      { 
       contributors[i].number = phone; 
       phone_correct = true; 
      } 
      else 
      { 
       cout << "Invalid phone number!! Please re-enter a 10 digit number: "; 
       cin >> phone; 
      } 
     } 
    }//End of phone member 

    {//Class of contributor 
    //Platinum Class 
     if (contributors[i].amount >= 10000) 
     { 
      contributors[i].class_con = "Platinum"; 
     } 
     //Diamond Class 
     else if (contributors[i].amount >= 5000 && contributors[i].amount <= 10000) 
     { 
      contributors[i].class_con = "Diamond"; 
     } 
     else if (contributors[i].amount >= 1000 && contributors[i].amount <= 5000) 
     { 
      contributors[i].class_con = "Gold"; 
     } 
     else 
     { 
      contributors[i].class_con = "Silver"; 
     } 
     cout << "\n"; 
    }//End of Class member 
} 
} 

void display() 
{ 
cout << "-------------------------" << endl; 
cout << "First Name, Last Name--Amount----Class----Telephone" << endl; 
cout << "-------------------------" << endl; 

for (int i = 0; i < ::count; i++) 
{ 
    cout << "\nName: " << contributors[i].firstName << " " << contributors[i].lastName << endl; 
    cout << "\nAmount Contributed: " << contributors[i].amount << endl; 
    cout << "\Class of Contributor: " << contributors[i].class_con << endl; 
    cout << "\nPhone: " << contributors[i].number << endl; 
    cout << "\n"; 
} 
for (int i = 0; i < ::count; i++) 
{ 
    ofstream file; 
    file.open("charity.txt"); 
    file <<"Name :"<< contributors[i].firstName << " " << contributors[i].lastName << endl; 
    file<<"Amount "<< contributors[i].amount << endl; 
    file<<"Class: "<< contributors[i].class_con << endl; 
    file<<"Telephone Number: "<< contributors[i].number << endl; 
    file << endl; 
    file.close(); 
} 
} 
//********************************* 

Answer 1

for(int i = 0; i < ::count; i++) 
{ 
    ofstream file; 
    file.open("charity.txt"); 
    file << ... 
    file.close(); 
} 

这是覆盖每一个文件打开时的旧数据。您应该打开该文件作为file.open("charity.txt", std::ios::app)以追加旧数据之后的数据。或者如下打开文件一次：

ofstream file; 
file.open("charity.txt"); 
for(int i = 0; i < ::count; i++) 
{ 
    file << ... 
} 
file.close();