store = input('Name of store: ')
food = input('Type of food served: ')
serverName = 'Will'
drinkPrice = '' #If it's a price (number why not set it to an integer example : drinkPrice = 0. '' refers to an empty string.
foodPrice = ''
drink = input('Hello! My name is {0} and I will be your server today! What can I get you to drink?: '.format(serverName))
if drink == "Water":
drinkPrice = 1
else : # in python if-else are written as elif <condition>: so it would be elif drink == "Coke":
if drink == "Coke":
drinkPrice = 2
else : # will never reach here
if drink == "Beer":
drinkPrice = 5
else : #will never reach here
print("The item you are trying to order is not on the menu!")
drink = input("What else would you like to drink?:") # you aren't looping here so you might want a loop.
food = input('What will you be ordering tonight?: ')
if food == "Steak":
foodPrice = 25
else : #same issue as the drink.
if food == "Pizza":
foodPrice = 10
else :
if food == "Salad":
foodPrice = 5
else :
print("The item that you are trying to order is not on the menu!")
totalPrice = str(drinkPrice) + str(foodPrice) #Python allows '+' to be used on strings as a form of concatination (combining strings).
#You want int(drinkPrice) + int(foodPrice) or just do drinkPrice + foodPrice
#since you set those value to 1, 2, 5, etc..
print('Thanks for eating at {0} and ordering {1} ! Server name: {2} Price total: {3}'.format(store, food, serverName, totalPrice))
要总结我的评论点：
如果语句写成如下：
if <condition>:
#do something
elif <condition>:
#do something
else:
#default if the top two didn't pass
您需要在循环读了，但我想你可能想要的是while循环：
while <condition>:
#loops until the condition is False
while循环的意义在于，您可以不断询问，直到获得您想要的有效答案。 See this link for more details
的Python允许在非数字使用+对象，如字符串：
x = "5"
y = "6"
print(x+y)
>> 56
你必须确保你的变量是数字：
x = 5
y = 6
print(x+y)
>> 11
“5”不一样5，第一个是5的字符串表示形式，后者是数字值5.这延伸到“”是一个空字符串不为0.
你的代码不起作用，所以你不应该担心微观优化。
这是你的代码应该是什么样子：
store = input('Name of store: ')
food = input('Type of food served: ')
serverName = 'Will'
drinkPrice = 0
foodPrice = 0
drink = input('Hello! My name is {0} and I will be your server today! What can I get you to drink?: '.format(serverName))
while drinkPrice == 0:
if drink == "Water":
drinkPrice = 1
elif drink == "Coke":
drinkPrice = 2
elif drink == "Beer":
drinkPrice = 5
else :
print("The item you are trying to order is not on the menu!")
drink = input("What else would you like to drink?:")
food = input('What will you be ordering tonight?: ')
while foodPrice == 0:
if food == "Steak":
foodPrice = 25
elif food == "Pizza":
foodPrice = 10
elif food == "Salad":
foodPrice = 5
else :
print("The item that you are trying to order is not on the menu!")
food = input("What else would you like to eat?:")
totalPrice = drinkPrice + foodPrice
print('Thanks for eating at {0} and ordering {1} ! Server name: {2} Price total: {3}'.format(store, food, serverName, totalPrice))
这个问题比堆栈溢出更适合于[代码审查（http://codereview.stackexchange.com）。 – CoryKramer
如果你有功能代码，那么这个问题可能更适合https://codereview.stackexchange.com/，但阅读[常见问题]（https://codereview.stackexchange.com/help/dont-ask）来检查是否这是关于话题 – EdChum
我不认为这会适合Code Review，因为代码中存在错误。 – MooingRawr