我有假期的数组:红宝石:分流/排序基于阵列的条件
Holiday.all
Holiday Load (0.7ms) SELECT "holidays".* FROM "holidays"
=> #<ActiveRecord::Relation [#<Holiday id: 1, name: "Dia da Confraternização Universal", holidayable_id: 1, holidayable_type: "Country", date: "2014-01-01", created_at: "2014-11-05 21:38:13", updated_at: "2014-11-05 21:38:13", verified?: false>, #<Holiday id: 2, name: "Natal", holidayable_id: 1, holidayable_type: "Country", date: "2014-12-25", created_at: "2014-11-05 22:02:33", updated_at: "2014-11-05 22:02:33", verified?: false>]>
我想用它的日期月至裂枣的这个大阵,所以我结束了12数组(每个月一个)。
你可以张贴实际的Ruby代码? – Stefan 2014-11-05 22:34:06
请全部给出一个数组的例子,用问题所需的少量元素以及所需的输出。 – 2014-11-05 23:00:45
如果您正在从数据库中检索这些数据,为什么不简单地重复几个月并逐月提取它们呢? – 2014-11-05 23:06:53