的MySQL查询无效：嵌套选择

Question

的过高的水平，我切换代码安德鲁斯解决方案：

SELECT s1.biz_name, s1.biz_info, s1.e_address, s1.e_city, s1.e_state, 
    s1.e_postal, s1.e_zip_full, s1.loc_LAT_centroid, s1.loc_LONG_centroid, 
    s1.biz_phone, s1.biz_phone_ext, s1.biz_fax, s1.biz_email, s1.web_url, 
    s2.upc as upc2, s2.retailprice as retailprice2, s2.dollar_sales as 
    dollar_sales2, s2.dollar_sales_ly as dollar_sales_ly2, s2.todaydate as 
    todaydate2, s2.datetimesql as datetimesql2, s2.shelfposition as 
    shelfposition2, s2.reg_sale as reg_sale2, s2.representative as 
    representative2, s2.notes as notes2, s3.upc as upc3, s3.retailprice as 
    retailprice3, s3.dollar_sales as dollar_sales3, s3.dollar_sales_ly as 
    dollar_sales_ly3, s3.todaydate as todaydate3, s3.datetimesql as 
    datetimesql3, s3.shelfposition as shelfposition3, s3.reg_sale as reg_sale3, 
    s3.representative as representative3, s3.notes as notes3, s4.upc as upc4, 
    s4.retailprice as retailprice4, s4.dollar_sales as dollar_sales4, 
    s4.dollar_sales_ly as dollar_sales_ly4, s4.todaydate as todaydate4, 
    s4.datetimesql as datetimesql4, s4.shelfposition as shelfposition4, 
    s4.reg_sale as reg_sale4, s4.representative as representative4, s4.notes as 
    notes4, s5.upc as upc5, s5.retailprice as retailprice5, s5.dollar_sales as 
    dollar_sales5, s5.dollar_sales_ly as dollar_sales_ly5, s5.todaydate as 
    todaydate5, s5.datetimesql as datetimesql5, s5.shelfposition as 
    shelfposition5, s5.reg_sale as reg_sale5, s5.representative as 
    representative5, s5.notes as notes5 
FROM allStores AS s1 
LEFT OUTER JOIN storeCheckRecords AS s2 
    ON s1.e_address = s2.e_address AND s2.upc = '650637119004' 
LEFT OUTER JOIN storeCheckRecords AS s3 
    ON s1.e_address = s3.e_address AND s3.upc = '650637119011' 
LEFT OUTER JOIN storeCheckRecords AS s4 
    ON s1.e_address = s4.e_address AND s4.upc = '650637374007' 
LEFT OUTER JOIN storeCheckRecords AS s5 
    ON s1.e_address = s5.e_address AND s5.upc = '650637374014' 
WHERE s2.e_address IS NOT NULL 
    OR s3.e_address IS NOT NULL 
    OR s4.e_address IS NOT NULL 
    OR s5.e_address IS NOT NULL 

这里是新的错误：查询无效：表过多; MySQL只能在一个连接中使用61个表格

任何其他想法？谢谢您的帮助。

Answer 1

这应该给你相同的结果，而无需使用子查询：

SELECT s1.biz_name, 
     ... 
     s2.upc    AS upc2, 
     ... 
     s3.upc    AS upc3, 
     ... 
     s4.upc    AS upc4, 
     ... 
     s5.upc    AS upc5, 
     ... 
FROM allStores AS s1 
LEFT OUTER JOIN storeCheckRecords AS s2 ON s1.e_address = s2.e_address 
LEFT OUTER JOIN storeCheckRecords AS s3 ON s1.e_address = s3.e_address 
LEFT OUTER JOIN storeCheckRecords AS s4 ON s1.e_address = s4.e_address 
LEFT OUTER JOIN storeCheckRecords AS s5 ON s1.e_address = s5.e_address 
WHERE (s2.e_address IS NOT NULL 
OR s3.e_address IS NOT NULL 
OR s4.e_address IS NOT NULL 
OR s5.e_address IS NOT NULL) 
AND (s2.upc = '650637119004' OR s2.upc IS NULL) 
AND (s3.upc = '650637119011' OR s3.upc IS NULL) 
AND (s4.upc = '650637374007' OR s4.upc IS NULL) 
AND (s5.upc = '650637374014' OR s5.upc IS NULL) 

Answer 2

可能与 MySQL bug #41156, List of derived tables acts like a chain of mutually-nested subqueries。

的错误日志表明它反对的MySQL 5.0.72，5.1.30和6.0.7验证。
在MySQL 5.1.37，MySQL 5.4.2（成为5.5.something）和NDB 7.1.0中修复。

---

关于上述问题的重新设计的查询：

枢轴查询可能会非常棘手。您可以使用Andrew在his answer中建议的方法。如果搜索许多UPC值，则需要编写应用程序代码来构建SQL查询，并追加与搜索的UPC值数量相同的JOIN子句。

的MySQL确实有对联接，可以在一个单一的查询进行数量限制，但例如，你应该没有达到极限。也就是说，您显示的查询确实有效。

我假设你正在展示一个例子查询搜索四个UPC码，而你的应用程序可以动态地构造查询的UPC代码数量更多，而且可能超过61的时候。

它看起来像您的查询的目标是返回拥有所列出的UPC代码的至少一个商店。你可以做更多的只是在下面的查询：

SELECT DISTINCT s.* 
FROM allStores AS s 
JOIN storeCheckRecords AS cr 
    ON s.e_address = cr.e_address 
    AND cr.upc IN ('650637119004','650637119011','650637374007','650637374014'); 

您可以在其他方面使用这种方法，例如查找具有的UPC的所有四店：

SELECT s.* 
FROM allStores AS s 
JOIN storeCheckRecords AS cr 
    ON s.e_address = cr.e_address 
    AND cr.upc IN ('650637119004','650637119011','650637374007','650637374014'); 
GROUP BY s.e_address 
HAVING COUNT(DISTINCT upc) = 4; 

或者找到存储了一些但不是所有四个的UPC的：

SELECT s.* 
FROM allStores AS s 
JOIN storeCheckRecords AS cr 
    ON s.e_address = cr.e_address 
    AND cr.upc IN ('650637119004','650637119011','650637374007','650637374014'); 
GROUP BY s.e_address 
HAVING COUNT(DISTINCT upc) < 4; 

或者找到商店缺乏的UPC的所有四个：

SELECT s.* 
FROM allStores AS s 
JOIN storeCheckRecords AS cr 
    ON s.e_address = cr.e_address 
    AND cr.upc IN ('650637119004','650637119011','650637374007','650637374014'); 
WHERE cr.e_address IS NULL; 

你还必须写一些代码来构建这个查询，但它是一个有点容易做的，它不超过上加入或可以运行子查询的数量的任何限制。

Answer 3

我将简化到只得到所有的元素先用一个简单的WHERE IN子句......你似乎是做了透视表显示T1到T2到T3到T4至T5。如果您获取了单个行中的所有数据，那么您可以在顶部显示STATIC列来显示每个行下面的详细信息。

SELECT 
     t1.brand, 
     t1.biz_name, 
     t1.biz_info, 
     t1.e_address, 
     t1.e_city, 
     t1.e_state, 
     t1.e_postal, 
     t1.e_zip_full, 
     t1.loc_LAT_centroid, 
     t1.loc_LONG_centroid, 
     t1.biz_phone, 
     t1.biz_phone_ext, 
     t1.biz_fax, 
     t1.biz_email, 
     t1.web_url, 
     t1.upc, 
     t1.retailprice, 
     t1.dollar_sales, 
     t1.dollar_sales_ly, 
     t1.todaydate, 
     t1.datetimesql, 
     t1.shelfposition, 
     t1.reg_sale, 
     t1.representative, 
     t1.notes 
    FROM 
     storeCheckRecords as t1 
    WHERE 
     t1.upc IN ('650637119004', '650637119011', '650637374007', '650637374014') 

等..

Brand Bus Addr     UPC  Retail$  Sales  Notes 
xyz Bus Name     UPC  ... etc... Cur Yr 
     Bus Info     Shelf Info    Last Yr 
     Address, (Cit/State/Zip) 
     Lat/Long 
     Phone/Fax 
     Email/Web 

---- 
Next Entry 

确实相同的地址是相同的，而不是谁携带的项目？如果一个条目是“123 Main St”，另一个是“123B Main St”，并且“123 Main St - Suite B”，那么您将找不到匹配项。

此外，你提到了一些最多有75个UPC代码......将它们放在一个单独的表中，并将其作为第一个表加入到“StoreCheckRecords”中，并将它们全部取出...而不是手动键入所有列后缀从2到75 ...或者在下一次运行中很多只有17个，而另一个4 ...我认为你可能太过于固定你试图从数据中获得的东西。

您甚至可以通过您最初想要基于该匹配的常见“e_address”进行GROUP，并将该组作为报告给用户的部分之间的中断。