如何使用XQuery连接相同的节点值

Question

我试图用XQuery将XML插入表中。有些节点是多个节点，但表中只有一列，所以我需要连接相同的节点。

如何迭代"INSERT ... SELECT ... FROM @xmlDoc.nodes ..."类型的查询。

这里是我的xml样本文件

<Persons> 
    <Person> 
     <FirstName>aaa</FirstName> 
     <LastName>bbb</LastName> 
     <DocumentNumber>AA 1234</DocumentNumber> 
     <DocumentNumber>BB 1234</DocumentNumber> 
     <WorkPlace>AAA Ltd</WorkPlace> 
     <WorkPlace>BBB Ltd</WorkPlace> 
    </Person> 
    <Person> 
     <FirstName>ccc</FirstName> 
     <LastName>ddd</LastName> 
     <DocumentNumber>CCC 1234</DocumentNumber> 
     <DocumentNumber>DDD 1234</DocumentNumber> 
     <DocumentNumber>EEE 1234</DocumentNumber>  
     <WorkPlace>CCC Ltd</WorkPlace> 
     <WorkPlace>DDD Ltd</WorkPlace> 
    </Person> 
</Persons> 

感谢。

Answer 1

这是一个使用cte的版本，首先在xml列中分离DocumentNumber和WorkPlace，然后使用xml路径（''）连接值。

declare @xml xml 
set @xml = 
' 
<Persons> 
    <Person> 
     <FirstName>aaa</FirstName> 
     <LastName>bbb</LastName> 
     <DocumentNumber>AA 1234</DocumentNumber> 
     <DocumentNumber>BB 1234</DocumentNumber> 
     <WorkPlace>AAA Ltd</WorkPlace> 
     <WorkPlace>BBB Ltd</WorkPlace> 
    </Person> 
    <Person> 
     <FirstName>ccc</FirstName> 
     <LastName>ddd</LastName> 
     <DocumentNumber>CCC 1234</DocumentNumber> 
     <DocumentNumber>DDD 1234</DocumentNumber> 
     <DocumentNumber>EEE 1234</DocumentNumber>  
     <WorkPlace>CCC Ltd</WorkPlace> 
     <WorkPlace>DDD Ltd</WorkPlace> 
    </Person> 
</Persons> 
' 

;with cte as 
(
    select 
    p.value('FirstName[1]', 'varchar(50)') as FirstName, 
    p.value('LastName[1]', 'varchar(50)') as LastName, 
    p.query('DocumentNumber') as docXML, 
    p.query('WorkPlace') as workXML 
    from 
    @xml.nodes('Persons/Person') p(p) 
) 
select 
    FirstName, 
    LastName, 
    (select d.value('.', 'varchar(100)')+' ' 
    from cte.docXML.nodes('DocumentNumber') d(d) 
    for xml path('')) as DocumentNumber, 
    (select w.value('.', 'varchar(100)')+' ' 
    from cte.workXML.nodes('WorkPlace') w(w) 
    for xml path('')) as WorkPlace 
from cte  

Answer 2

你的XML组织很差.....麻烦是<DocumentNumber>和<WorkPlace>实体里面直接<Person>，而不是在他们自己的“容器”节点的多个条目。

这使得极难得到这个正确解析.....

如果你想抓住唯一的名称，你可以这样做：

DECLARE @input XML = '<Persons> 
    <Person> 
     <FirstName>aaa</FirstName> 
     <LastName>bbb</LastName> 
     <DocumentNumber>AA 1234</DocumentNumber> 
     <DocumentNumber>BB 1234</DocumentNumber> 
     <WorkPlace>AAA Ltd</WorkPlace> 
     <WorkPlace>BBB Ltd</WorkPlace> 
    </Person> 
    <Person> 
     <FirstName>ccc</FirstName> 
     <LastName>ddd</LastName> 
     <DocumentNumber>CCC 1234</DocumentNumber> 
     <DocumentNumber>DDD 1234</DocumentNumber> 
     <DocumentNumber>EEE 1234</DocumentNumber>  
     <WorkPlace>CCC Ltd</WorkPlace> 
     <WorkPlace>DDD Ltd</WorkPlace> 
    </Person> 
</Persons>' 

SELECT 
    Person.value('(FirstName)[1]', 'varchar(50)') 'First Name', 
    Person.value('(LastName)[1]', 'varchar(50)') 'Last Name' 
FROM 
    @input.nodes('/Persons/Person') AS Persons(Person) 

，当然，你可以在选择存储信息之前，还要执行INSERT INTO dbo.YourTable(FirstName, LastName)。

但再次：试图让那些<DocumentNumber>和<WorkPlace>节点成合适的格式是真的真的很难.....你要么最终会复制数据，或者你必须做的第二和第三解析通拿到这个东西妥善保存。