如何通过线从字符串中读取数据线缓冲区和匹配另一个字符串

Question

我写的代码

public class keys { 

    private static final String[] keyss = { 
     "HGDLV-KLLQC-DM3ON-MAUOX-FNQK5", 
     "HQKLD-NYRDL-NJXCV-BVCKF-NRKLC", 
     "LDFCV-BDJCQ-VMFQV-FNRKC-NFCFL" 
     //and many more 
    }; 

    public static String getKey(String key) { 
     boolean b = Arrays.asList(keyss).contains(key); 
     if (b == true) { 
      key = "approved"; 
     } else { 
      key = "unapproved"; 
     } 
     return key; 
    } 

，并得到批准的所有字符串，即使上述这么想的匹配与用户指定的字符串

Answer 1

使用equals比较字符串。此外getKeys的（）实现过于复杂，冗余..考虑将其更改为：

public class Keys { 
    private static final String[] keys = { 
     "HGDLV-KLLQC-DM3ON-MAUOX-FNQK5", 
     "HQKLD-NYRDL-NJXCV-BVCKF-NRKLC", 
     "LDFCV-BDJCQ-VMFQV-FNRKC-NFCFL" 
     //and many more 
    }; 

    public static String getKey(String key) { 
     for(String current : keys){ 
      if(current.equals(key)){ 
       return "approved"; 
      } 
     } 
     return "unapproved"; 
    } 
} 

没有必要在你使用它的方式，也不是boolean开关使用Arrays ..

你可能想要查看this question来阅读有关比较字符串的内容。