获得使用PHP

我有麻烦的属性从地图内。例如下面获得使用PHP

<area shape="poly" class="areaSelect" coords="475,241,495,220,515,215,531,226,534,262,530,290,493,307,472,287" href="http://www.someURL" title="Area Title" alt="Link Title"/>

我一直在使用simple_html_dom.php来检索页面的其他元素XHTML地图区域COORDS。任何帮助将不胜感激。正如我一直在绕过这个，我尝试了使用Xpath并加载XHTML文件，但是当我尝试获得这些坐标时，我只有42个“DOMAttr Object（）”的情况，地图上有42个区域，但.. .... 帮帮我！

来源

2011-08-25 apeitup

你需要得到COORDS的所有值，是吗？ –

谢谢Tuga，但这个地方是纯粹的灵感。我已经搜索了最近两天试图解决这个问题。当我发布这个问题的时候，我偶然发现了一些能够给我答案的东西。我会稍后将解决方案发布到我自己的问题上。我应该在几年前加入这里，这会为我节省大量头痛。 – apeitup

解决方案是使用DomDocument？ :) –

好的，我会尽力为任何想做类似事情的人提供尽可能多的细节。

这是一个快速示例文件。

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"  "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> 
    <html xmlns="http://www.w3.org/1999/xhtml"> 
    <head> 
    <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> 
    <title>Untitled Document</title> 
    <style> 
    body{font:Arial, Helvetica, sans-serif;} 
    </style> 
</head> 
<body> 
<div class="title" style="font-size: 14px; color: #009"><h2>Get any information</h2>  </div> 
<div id="image-holder"> 
<img src="http://mrg.bz/sb3gG9" alt="microchips" width="496px" height="343px" border="0" usemap="#MicroChips"/> 
<map name="MicroChips" id="MicroChips2"> 
    <area class="areaSelect" shape="poly" coords="46,91,157,43,217,106,101,159" href="http://www.someplace.com" title="Main Chip" alt="Main Chip" /> 
</map> 
<div id="body" style="width:496px"> 
    <p>This is to demonstrate how to get as much out of a file as possible. Well a least some of it anyway.</p> 
    <p>Here is another paragraph to show how to get multiple items</p> 
</div> 
</div> 
</body> 
</html>

好吧，现在这里是PHP。您需要下载'PHP Simple HTML DOM Parser'并将其加载到您的测试服务器上。以便您可以访问其他功能。

<?php 
    include('simple_html_dom.php'); //Load/include the PHP Simple HTML DOM Parser 

    $html = file_get_html('http://www.YourServer.com/test.html'); // Load your html file 

    // create a series of variables to call on later 

    $imgtitle = $html->find('div.title', 0)->plaintext; //here we reference the HTML file, and find the div with the class "title" and display it as plaintext 

    // ok for some reason and hopefully someone out there can add why 
    // I had to reference the fist instance of each element here 
    // referenced as the ',0' in each case. 

    // here you can see we search for the div 'image-holder' 
    // and then search in that div for the first image and save it to a variable 

    $imageurl = $html->find('#image-holder',0)->find('img',0); 

    // here we target the image scr, width, height, style, alt, border and usemap and assign them to variables 

    $imagesrc = $imageurl->src; 
    $imageWidth = $imageurl->width; 
    $imageHeight = $imageurl->height; 
    $imageStyle = $imageurl->style; 
    $imageAlt = $imageurl->alt; 
    $imageBrd = $imageurl->border; 
    $imageUsemap = $imageurl->usemap; 

    $map = $html->find('map',0); // here we look for the map and assign it to a variable 

    // here we target the map ID and Name and usemap and assign them to variables 

$mapID = $map->id; 
$mapName = $map->name; 

    // we assigned a class to the map areas to find them easier 
    $imgmaparea = $html->find('.areaSelect'); 

    // ok although the example only has one map area this will find multiple 
    // areas and print them on the screen using the 'foreach' function 
    foreach ($imgmaparea as $value){ 
    $areaShape = $value->shape; 
    $areaCoords = $value->coords; 
    $areaHref = $value->href; 
    $areaTitle = $value->title; 
    $areaAlt = $value->alt; 
     // print them on the screen 
     echo 'Shape: '.$areaShape. '<br>'; 
    echo 'Coords: '.$areaCoords. '<br>'; 
     echo 'Href: '.$areaHref. '<br>'; 
     echo 'Title: '.$areaTitle. '<br>'; 
     echo 'Alt: '.$areaAlt. '<br>'; 

    } 
     // print them on the screen 
     echo 'name: '.$mapName. '<br>'; 
     echo 'Id: '.$mapID. '<br>'; 
     echo 'filename: '.$filename. '<br>'; 
     echo 'Src: '.$imagesrc. '<br>'; 
     echo 'Width: '.$imageWidth. '<br>'; 
     echo 'Height: '.$imageHeight. '<br>'; 
     echo 'Style: '.$imageStyle. '<br>'; 
     echo 'Alt: '.$imageAlt. '<br>'; 
     echo 'Usemap: '.$imageUsemap. '<br>'; 

    ?>

我试图彻底解释，但如果任何人有任何问题或建议，我会很高兴在这里他们

来源

2011-08-29 23:56:28 apeitup

获得使用PHP

回答

相关问题