awk脚本调整格式

Question

我尝试使用以下awk脚本来算从文件名为file.txt每1000个记录和括号括之间的那些记录

file.txt的内容

awk '{ printf $0 " " } NR%1000 == 0 { print "" }' file.txt | sed 's/.*/(&)/' 

输出

(12345 23456 43567) 

我需要assotciate此输出与MySQL的批量删除语句下面

Delete from ReportingDetail where ReportingDetailID IN (12345,23456,43567); 

1. 我无法添加“从ReportingDetail删除此类其中 ReportingDetailID IN“到每一行的结尾。
2. 我无法在记录之间添加“，”。

您的帮助非常感谢！

Answer 1

你只能使用sed做到这一点：

sed -e 's/ /,/g' -e 's/^/Delete from ReportingDetail where ReportingDetailID IN (/' -e 's/$/)/' file.txt 

如：

$ echo "1 2 3"|sed -e 's/ /,/g' -e 's/^/Delete from ReportingDetail where ReportingDetailID IN (/' -e 's/$/)/' 
Delete from ReportingDetail where ReportingDetailID IN (1,2,3) 

编辑 - 为您的更新（即当你在不同线路上的数字），只是在前面加上你已经有什么：

awk '{ printf $0 " " } NR%1000 == 0 { print "" }' file.txt | sed -e 's/ /,/g' -e 's/^/Delete from ReportingDetail where ReportingDetailID IN (/' -e 's/,$/)/' 

如：

$ echo -e "1\n2\n3"|awk '{ printf $0 " " } NR%1000 == 0 { print "" }'|sed -e 's/ /,/g' -e 's/^/Delete from ReportingDetail where ReportingDetailID IN (/' -e 's/,$/)/' 
Delete from ReportingDetail where ReportingDetailID IN (1,2,3) 

你也可以做，如果没有这样的AWK：

$ echo -e "1\n2\n3\n4"|tr "\n" " "|sed -e 's/ /,/g' -e 's/^/Delete from ReportingDetail where ReportingDetailID IN (/' -e 's/,$/)/' 
Delete from ReportingDetail where ReportingDetailID IN (1,2,3,4) 

注意我使用的回声只是为了测试，即这是它产生：

$ echo -e "1\n2\n3\n4" 
1 
2 
3 
4