2011-03-15 58 views
3

我想在我的Android应用程序中发送多部分窗体,但不使用org.apache.http.entity.mime所以我创建了mu自己的方式,但它不起作用办法我是如何创建的请求:在Android中通过HttpURLConnection(POST)发送多部分窗体

public byte[] createRequest(byte[] imagedata){ 
    byte[] requestData = null; 
    ByteArrayOutputStream buf = new ByteArrayOutputStream(); 
    OutputStreamWriter output = null; 
    try { 
     Log.i(TAG, "Creating request"); 
     output = new OutputStreamWriter(buf, "UTF-8"); 
     output.write("--"); 
     output.write(boundary); 
     output.write("\r\n"); 
     output.write("Content-Disposition: form-data; name=\"auth\"; filename=\"auth\"\r\n"); 
     output.write("Content-Type: text/xml; charset=utf-8\r\n"); 
     output.write("\r\n"); 

     byte temp2[] = buf.toByteArray(); 
     Log.i(TAG, "BUF SIZE: " + temp2.length); 

     Log.i(TAG, "BUF: " + buf.toString()); 
     ByteArrayOutputStream authBuffer = new ByteArrayOutputStream(); 
     OutputStreamWriter authOut = new OutputStreamWriter(authBuffer, "UTF-8"); 
     writeAuthRequestFragment(user, pass, company_id, "RESLINK CLIENT", "2.0", null, null, null, authOut); 

     buf.write(authBuffer.toByteArray()); 

     Log.i(TAG, "BUF SIZE: " + buf.size()); 

     output.write("\r\n--" + boundary + "\r\n"); 
     output.write("Content-Disposition: form-data; name=\""+CIMAGE+"\"; filename=\""+CIMAGE+"\"\r\n"); 
     output.write("Content-Type: "+IMAGE_PNG+"\r\n"); 
     output.write("\r\n"); 
     buf.write(imagedata); 
     output.write("\r\n--" + boundary + "--\r\n"); 
     requestData = buf.toByteArray(); 
     Log.i(TAG, "WHOLE SIZE " + requestData.length); 
     output.flush(); 
    } catch(IOException ex){ 
     ex.printStackTrace(); 
    } 
    finally{ 
     if(buf!=null){ 
      try { 
       buf.close(); 
      } catch (IOException e) { 
       e.printStackTrace(); 
      } 
     } 
     if(output!=null){ 
      try { 
       output.close(); 
      } catch (IOException e) { 
       e.printStackTrace(); 
      } 
     } 
    } 
    return requestData; 
} 

当方法被调用日志信息显示,ByteArrayOutputStream有大小为0的那一刻,当我加入的图象 - 所以它看起来像使用OutputStreamWriter不写串,还是我错了?

任何建议或解决方案?

+0

为什么你调用flush()在输出作家** **后您的日志信息? – HefferWolf 2011-03-15 08:35:43

+0

其实问题解决了,我只是不知道为什么它不写我什么我的意思是outputStreamWriter – Robert 2011-03-15 10:20:43

回答

5

如果有人将寻找答案这里是我如何做它:

private byte[] generatePhotoRequest(byte[] imagedata){ 
    byte[] requestData = null; 
    ByteArrayOutputStream bufer = new ByteArrayOutputStream(); 
    DataOutputStream dataOut = new DataOutputStream(bufer); 
    try{ 
     dataOut.writeBytes("--"); 
     dataOut.writeBytes(BOUNDARY); 
     dataOut.writeBytes("\r\n"); 
     dataOut.writeBytes("Content-Disposition: form-data; name=\"auth\"; filename=\"auth\"\r\n"); 
     dataOut.writeBytes("Content-Type: text/xml; charset=utf-8\r\n"); 
     dataOut.writeBytes("\r\n"); 
     dataOut.write(generateAuth()); 
     dataOut.writeBytes("\r\n--" + BOUNDARY + "\r\n"); 
     dataOut.writeBytes("Content-Disposition: form-data; name=\""+CIMAGE+"\"; filename=\""+CIMAGE+"\"\r\n"); 
     dataOut.writeBytes("Content-Type: "+IMAGE_PNG+"\r\n"); 
     dataOut.writeBytes("\r\n"); 
     bufer.write(imagedata); 
     dataOut.writeBytes("\r\n"); 
     dataOut.writeBytes("\r\n--" + BOUNDARY + "--\r\n"); 

     requestData = bufer.toByteArray(); 
    } catch(IOException ex){ 
     ex.printStackTrace(); 
    } finally{ 
     if(bufer!=null){ 
      try { 
       bufer.close(); 
      } catch (IOException e) { 
       // TODO Auto-generated catch block 
       e.printStackTrace(); 
      } 
     } 
    } 
    return requestData; 
} 
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