如何在matlab中使用quadgk函数作为函数句柄？

Question

我想解决一个双积分，我正在解决内部以及与quadgk函数外部积分。

% The integrand is of course a function of both x and y 
integrand = @(x,y) (phi(j,y,X) - phi(j,x,X))*(phi(i,y,X) - phi(i,x,X))/abs(y-x)^(2*s+1) 

% The inner integral is a function of x, and integrates over y 
inner = @(x) quadgk(@(y)integrand(x,y), x-lambda, x+lambda) 

% The inner integral is integrated over x to yield the value of the double integral 
dblIntegral = quadgk(inner, -(1+lambda), 1+lambda) 

和我得到这个以下错误：

integrand = @(x,y)(phi(j,y,X)-phi(j,x,X))*(phi(i,y,X)-phi(i,x,X))/abs(y-x)^(2*s+1) 
inner = @(x)quadgk(@(y)integrand(x,y),x-lambda,x+lambda) 

??? Error using ==> quadgk at 108 
A and B must be scalar floats. 

Error in ==> @(x)quadgk(@(y)integrand(x,y),x-lambda,x+lambda) 
Error in ==> quadgk>evalFun at 344 
     fx = FUN(x); 

Error in ==> quadgk>f1 at 362 
    [y,too_close] = evalFun(tt); 

Error in ==> quadgk>vadapt at 258 
     [fx,too_close] = f(x); 

Error in ==> quadgk at 197 
[q,errbnd] = vadapt(@f1,interval); 

Error in ==> frational_laplacian at 29 
dblIntegral = quadgk(inner, -(1+lambda), 1+lambda) 

Answer 1

你得到的问题，因为内部quadgk使用评估值的矢量传递的功能。这意味着，在该线

dblIntegral = quadgk(inner, -(1+lambda), 1+lambda) 

功能inner被称为其中x是一个矢量。 quadgk要求a和b（在这种情况下x±lambda）是标量，所以你会看到你所看到的错误。如果你想确保inner总是得到一个标量作为输入，你可以使用

dblIntegral = quadgk(@(x)arrayfun(inner,x), -(1+lambda), 1+lambda)