如何编写一个计算python总点数的函数？

Question

如何编写一个函数，根据python计算总点数？

例如，

 rank_list=[['Peter','Amy','John','Kitty'],['Amy','John','Kitty','Peter']] 

人们得到5分为第一等级，2分，为第二，0点为第三和9点到最后。

我想要一个清单来计算总人数

Answer 1

这是否适合您？

In [277]: rank_list=[['Peter','Amy','John','Kitty'],['Amy','John','Kitty','Peter']] 

In [278]: points = collections.defaultdict(int) 

In [279]: for rank_lis in rank_list: 
    .....:  for score, person in ran 
random  range  rank_list 
    .....:  for score, person in enumerate(rank_lis[::-1]): 
    .....:   points[person] += score 
    .....:   

In [280]: points.items() 
Out[280]: [('Amy', 5), ('John', 3), ('Kitty', 1), ('Peter', 3)] 

一个更有效的解决方案：

In [285]: rank_list=[['Peter','Amy','John','Kitty'],['Amy','John','Kitty','Peter']] 

In [286]: for rank_lis in rank_list: 
    for score, person in enumerate(rank_lis, -3): 
     points[person] -= score 
    .....:   

In [287]: points.items() 
Out[287]: [('Amy', 5), ('Peter', 3), ('Kitty', 1), ('John', 3)] 

Answer 2

您可以使用defaultdict： -

rank_list=[['Peter','Amy','John','Kitty'],['Amy','John','Kitty','Peter']] 
my_dict = {0:3, 1:2, 2:1, 3:0} # Have a mapping from index to score 

from collections import defaultdict 

ranking = defaultdict(int) 

for elem in rank_list: 
    for index, value in enumerate(elem): 
     ranking[value] += my_dict[index] 

print ranking.items() 

OUTPUT： -

[('Amy', 5), ('Kitty', 1), ('Peter', 3), ('John', 3)] 

Answer 3

我们荷兰国际集团的反向列表作为索引（因为0 = 3,3 = 0，等），并将其保存到一个词典：

d = {} 
for list in rank_list: 
    for name in list: 
    if name in d: 
     d[name] = d[name] + list[::-1].index(name) 
    else: 
     d[name] = list[::-1].index(name) 

list[::-1]输出反向列表。另外，您还可以通过打印d['Peter']来获得分数。

Answer 4

它看起来像collections.Counter工作：

from collections import Counter 

rank_list=[['Peter','Amy','John','Kitty'],['Amy','John','Kitty','Peter']] 
rank_by_place = (3, 2, 1, 0) 

ranks = Counter() 
for record in rank_list: 
    for name, rank in zip(record, rank_by_place): 
     ranks.update({name: rank}) 

print ranks.most_common() # ordered by rank