JSON解析值不显示

所以我使用JSON.net解析我的JSON，但我得到了错误的输出为List of List值对象。这里是我的JSON.net代码：JSON解析值不显示

var reader = new StreamReader(GenerateStreamFromString(decodedString)); 
      var rootObject = JsonConvert.DeserializeObject<RootObject>(reader.ReadToEnd()); 

txtOut.Text = rootObject.Results.output1.value.ColumnNames[0].ToString() + " : " + 
rootObject.Results.output1.value.Values[0].ToString();

这里是JSON类：

public class Value 
{ 
    public List<string> ColumnNames { get; set; } 
    public List<string> ColumnTypes { get; set; } 
    public List<List<string>> Values { get; set; } 
} 

public class Output1 
{ 
    public string type { get; set; } 
    public Value value { get; set; } 
} 

public class Results 
{ 
    public Output1 output1 { get; set; } 
} 

public class RootObject 
{ 
    public Results Results { get; set; } 
}

输出应该是：

Scored Probabilities for Class "BackPocket" : 0.37687685364

虽然我得到：

Scored Probabilities for Class "BackPocket" : System.Collections.Generic.List`1[System.String]

我在哪里做错了？

谢谢。

P.S.下面是一个简单的JSON：

{"Results":{"output1":{"type":"table","value":{"ColumnNames":["Scored Probabilities for Class \"BackPocket\"","Scored Probabilities for Class \"Ear\"","Scored Probabilities for Class \"Handbag\"","Scored Probabilities for Class \"SidePocket\"","Scored Labels"],"ColumnTypes":["Double","Double","Double","Double","String"],"Values":[["0.0249993801116943","0.999469399452209","0.00426889630034566","0.00104729761369526","Ear"]]}}}}

来源

2016-09-15 Jeet.Deir

您的JSON是无效的。请查看http://json2csharp.com/# –

为什么它应该是第一个值而不是'List'？毕竟你有一个列表清单，所以你需要指定你想要的那个“二级”列表的元素 – UnholySheep

@ShannonHolsinger只是检查和纠正。 –

这是一个列表的列表。您目前只索引一个级别的深度。您需要深入索引两个级别。

txtOut.Text = rootObject.Results.output1.value.ColumnNames[0].ToString() + " : " + 
rootObject.Results.output1.value.Values[0][0].ToString();

来源

2016-09-15 20:44:40

尝试这是您的JSON类/类

[DataContract]  
public class Value 
{ 
[DataMember] 
public List<string> ColumnNames { get; set; } 
[DataMember] 
public List<string> ColumnTypes { get; set; } 
[DataMember] 
public List<List<string>> Values { get; set; } 
} 
[DataContract] 
public class Output1 
{ 
[DataMember] 
public string type { get; set; } 
[DataMember] 
public Value value { get; set; } 
} 
[DataContract] 
public class Results 
{ 
[DataMember] 
public Output1 output1 { get; set; } 
} 
[DataContract] 
public class RootObject 
{ 
[DataMember] 
public Results Results { get; set; } 
}

来源

2016-09-15 20:44:10

不需要这些属性.... –

是的，他们被自动添加 - 只要确保他的Json是正确的，因为我不是当OP第一次发布时。 –

因为元素0是一个列表，您可以使用string.Join获得打印字符串..

txtOut.Text = rootObject.Results.output1.value.ColumnNames[0].ToString() + " : " + 
       string.Join(";",rootObject.Results.output1.value.Values[0]);

输出为：

Scored Probabilities for Class "BackPocket" : 0.0249993801116943;0.999469399452209;0.00426889630034566;0.00104729761369526;Ear

来源

2016-09-15 20:46:53

JSON解析值不显示

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