字符串转换为2位小数

Question

我有一个字符串（确认是十进制表达） 0.4351242134

我想转换成字符串以两个小数位 0.44

我应该如何在C＃中做？

Answer 1

var probablyDecimalString = "0.4351242134"; 
decimal value; 
if (Decimal.TryParse(probablyDecimalString , out value)) 
    Console.WriteLine (value.ToString("0.##")); 
else 
    Console.WriteLine ("not a Decimal"); 

Answer 2

float f = float.Parse("0.4351242134"); 
Console.WriteLine(string.Format("{0:0.00}", f)); 

见this为的String.format。

Answer 3

var d = decimal.Parse("0.4351242134"); 
Console.WriteLine(decimal.Round(d, 2)); 

Answer 4

嗯，我会做：

var d = "0.4351242134"; 
Console.WriteLine(decimal.Parse(d).ToString("N2")); 

Answer 5

这会帮助

double ValBefore= 0.4351242134; 
double ValAfter= Math.Round(ValBefore, 2, MidpointRounding.AwayFromZero); //Rounds"up" 

Answer 6

float myNumber = float.Parse("0.4351242134"); 
Console.WriteLine(string.Format("{0:f2}", myNumber)); 

https://msdn.microsoft.com/en-us/library/s8s7t687.aspx