Javascript-Ajax无法发送任何数据

Question

我无法使代码的这部分工作，基本上我想调用这个函数，它发送一个变量到一个php页面。我测试了变量是否存在，并且测试了我的php页面正在接受信息，但是我无法使这个Ajax工作。

function ajaxRequest(myname) { 
var AJAX = null; // Initialize the AJAX variable. 
if (window.XMLHttpRequest) 
{ // Does this browser have an XMLHttpRequest object? 
    AJAX=new XMLHttpRequest(); // Yes -- initialize it. 
} else 
{ // No, try to initialize it IE style 
    AJAX=new ActiveXObject("Microsoft.XMLHTTP"); // Wheee, ActiveX, how do we format c: again? 
} // End setup Ajax. 

if (AJAX==null) 
{ // If we couldn't initialize Ajax... 
    alert("Your browser doesn't support AJAX."); // Sorry msg. 
return false // Return false, couldn't set up ajax 
} 
AJAX.onreadystatechange = function() 
{ // When the browser has the request info.. 
    if (AJAX.readyState==4 || AJAX.readyState=="complete") 
    { // see if the complete flag is set. 
     callback(AJAX.responseText, AJAX.status); // Pass the response to our processing function 
    } // End Ajax readystate check. 
} 

alert("Alert1"); 
var url='http://localhost/main.php?Name=myname';  
AJAX.open("POST", url, true); // Open the url this object was set-up with. 
alert("Alert2"); 
AJAX.send(); // Send the request. 

}

这是我的PHP一部分应该接受变量

<?php 
$var=$_GET['Name']; 

echo $var; 
?> 

Answer 1

好吧，首先，你需要改变你的请求，从POST 来得到这样

AJAX.open("GET", url, true); // Open the url this object was set-up with. 

而且您还需要更新此行 从

var url='http://localhost/main.php?Name=myname'; 

到

var url='http://localhost/main.php?Name='+myname; 

我完整的脚本是：

<script type="text/javascript"> 
    function ajaxRequest(myname) { 
     var AJAX = null; // Initialize the AJAX variable. 
     if (window.XMLHttpRequest) 
     { // Does this browser have an XMLHttpRequest object? 
      AJAX=new XMLHttpRequest(); // Yes -- initialize it. 
     } else { // No, try to initialize it IE style 
      AJAX=new ActiveXObject("Microsoft.XMLHTTP"); // Wheee, ActiveX, how do we format c: again? 
     } // End setup Ajax. 

     if (AJAX==null) 
     { // If we couldn't initialize Ajax... 
      alert("Your browser doesn't support AJAX."); // Sorry msg. 
      return false // Return false, couldn't set up ajax 
     } 

     AJAX.onreadystatechange = function() 
     { // When the browser has the request info.. 
      if (AJAX.readyState==4 || AJAX.readyState=="complete") 
      { // see if the complete flag is set. 
       callback(AJAX.responseText, AJAX.status); // Pass the response to our processing function 
      } // End Ajax readystate check. 
     } 

     alert("Alert1"); 
     var url='http://localhost/main.php?Name='+myname;  
     AJAX.open("GET", url, true); // Open the url this object was set-up with. 
     alert("Alert2"); 
     AJAX.send(); // Send the request. 
    } 
</script> 

，你也可能会丢失，使其看起来像这样

function callback(x, y) { 
    alert(x); 
} 

回调函数，以便将其添加

并调用你的AJAX函数由

ajaxRequest("ashley"); 

这是你需要main.php代码（尽管这不是你应该使用AJAX的

<?php 
session_start(); 
if(isset($_GET["Name"])) { 
    $_SESSION["Name"] = $_GET["Name"]; 
} 
if(isset($_SESSION["Name"])) { 
    echo $_SESSION["Name"]; 
} else { 
    echo "The AJAX has not been run!"; 
} 
?> 

Answer 2

什么有两种方法来发送一个Ajax请求到服务器 GET或POST

1. GET方法：

var url='http://localhost/main.php?Name='+myname; // you can add any numner of vars here 
AJAX.open("GET", url, true); 
AJAX.send(); 

代码在main.php

if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') { 
     echo $_GET['Name']; 
    } 

2. POST方法：

AJAX.open("POST","ajax_test.asp",true); 
AJAX.setRequestHeader("Content-type","application/x-www-form-urlencoded"); 
AJAX.send("Name="+myname); 

守则main.php

if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') { 
    echo $_POST['Name']; 
}