这里没有游标，但这仍然是循环使用递归CTE找出哪些行应该组合在一起。临时表#T用于容纳将行连接到彼此的ID。它可以在没有临时表的情况下完成，但出于性能方面的原因，最好使用临时表来完成，而不是使用另一个CTE作为递归CTE的源。
在最后一个查询中，我使用for xml path技巧连接了来自No的值。这意味着CTE C被再次使用，所以它将被执行两次。您可能需要将该CTE转换为临时表以避免这种情况。
SQL Fiddle
MS SQL Server 2008的架构设置：
create table YourTable
(
GUID varchar(4),
No varchar(2),
sDateTime datetime,
eDateTime datetime,
Name varchar(1)
);
insert into YourTable values
('0000', '01', '2013-02-02 08:00:00', '2013-02-02 08:40:00', 'A'),
('0000', '02', '2013-02-02 08:45:00', '2013-02-02 09:45:00', 'A'),
('0000', '03', '2013-02-02 11:30:00', '2013-02-02 12:00:00', 'A'),
('0000', '04', '2013-02-02 09:55:00', '2013-02-02 11:00:00', 'A'),
('0000', '05', '2013-02-02 11:05:00', '2013-02-02 12:30:00', 'B');
查询1：
create table #T
(
ID int,
GUID varchar(4),
No varchar(2),
sDateTime datetime,
eDateTime datetime,
Name varchar(1),
primary key(ID, GUID, Name)
);
insert into #T(ID, GUID, No, sDateTime, eDateTime, Name)
select row_number() over(partition by GUID, Name order by sDateTime),
GUID, No, sDateTime, eDateTime, Name
from YourTable;
with C as
(
select T.ID, T.GUID, T.No, T.sDateTime, T.eDateTime, T.Name, 1 as Grp
from #T as T
where T.ID = 1
union all
select T.ID, T.GUID, T.No, T.sDateTime, T.eDateTime, T.Name,
C.Grp + case when datediff(minute, C.eDateTime, T.sDateTime) > 10
then 1
else 0
end
from #T as T
inner join C
on T.ID = C.ID + 1 and
T.Name = C.Name and
T.GUID = C.GUID
)
select C.GUID,
(
select ','+C2.No
from C as C2
where C.GUID = C2.GUID and
C.Name = C2.Name and
C.Grp = C2.Grp
order by C2.No
for xml path(''), type
).value('substring(text()[1], 2)', 'varchar(max)') as No,
min(C.sDateTime) as sDateTime,
max(C.eDateTime) as eDateTime,
C.Name
from C
group by C.GUID, C.Name, C.Grp
drop table #T;
Results：
| GUID | NO | SDATETIME | EDATETIME | NAME |
----------------------------------------------------------------------------------------------
| 0000 | 01,02,04 | February, 02 2013 08:00:00+0000 | February, 02 2013 11:00:00+0000 | A |
| 0000 | 03 | February, 02 2013 11:30:00+0000 | February, 02 2013 12:00:00+0000 | A |
| 0000 | 05 | February, 02 2013 11:05:00+0000 | February, 02 2013 12:30:00+0000 | B |
仅供参考，SQL Server 2012版本。
with CMinDiff as
(
select GUID, No, sDateTime, eDateTime, Name,
case when datediff(minute,
coalesce(lag(eDateTime) over(partition by GUID, Name
order by eDateTime),
sDateTime),
sDateTime) <= 10
then 0
else 1
end as MinDiff
from YourTable
), CSumMinDiff as
(
select GUID, No, sDateTime, eDateTime, Name,
sum(MinDiff) over(partition by GUID, Name
order by sDateTime
rows between unbounded preceding and current row) as Grp
from CMinDiff
)
select C.GUID,
(
select ','+C2.No
from CSumMinDiff as C2
where C.GUID = C2.GUID and
C.Name = C2.Name and
C.Grp = C2.Grp
order by C2.No
for xml path(''), type
).value('substring(text()[1], 2)', 'varchar(max)') as No,
min(C.sDateTime) as sDateTime,
max(C.eDateTime) as eDateTime,
C.Name
from CSumMinDiff as C
group by C.GUID, C.Name, C.Grp
您正在使用哪种SQL Server版本？ – 2013-02-12 21:59:30
@NitinMidha SQL Server 2008 Express Edition – 2013-02-12 22:01:20
另外为什么05不与01,02和04组合？我认为它符合10分钟的标准，如果我理解正确。 – 2013-02-12 22:03:15