Java的正则表达式通配符不接受

Question

String depends2 = "success(job1) AND n(job2)"; 
depends2 = depends2.replaceAll("[\\s].(?i)[snd][\\s]*\\(", "");  
System.out.println(depends2); 

我预计这将输出

success(job1) ANDjob2) 

相反，它输出

success(job1) AND n(job2) 

Answer 1

[\\s].(?i)[snd]这在你的正则表达式保证一定有一个当前字符其间的空间和n （后面跟着零或更多空格加上(符号）。但实际上并没有一个角色。所以你的正则表达式失败并且返回原始字符串而不做任何替换。

String depends2 = "success(job1) AND n(job2)"; 
depends2 = depends2.replaceAll("\\s(?i)[snd]\\s*\\(", "");  
System.out.println(depends2); 

输出：

success(job1) ANDjob2) 

说明：

\s      whitespace (\n, \r, \t, \f, and " ") 
(?i)      set flags for this block (case- 
         insensitive) (with^and $ matching 
         normally) (with . not matching \n) 
         (matching whitespace and # normally) 
[snd]     any character of: 's', 'n', 'd' 
\s*      whitespace (\n, \r, \t, \f, and " ") (0 or 
         more times) 
\(      '('