价值的类型'（任何） - >（）'没有成员'currentTitle'

Question

我是一个新手来迅速和我在一个井字游戏应用程序的工作。我试图写出你决定胜利者的部分。我告诉计算机，如果连续三个按钮有相同的x和o文本，则显示赢家在名为Winner的标签上。但是我得到一个错误：“类型'（Any） - >（）'的值没有成员'currentTitle'。” 这里是我的代码：

//Winner X 
    if (Buttontl1.currentTitle == "X" && Buttontm1.currentTitle == "X" && Buttontr1.currentTitle == "X") 
    { 
     Winner.text = "Player X wins!" 
    } 
    else if Buttonml1.currentTitle == "X" && Buttonm1.currentTitle == "X" && Buttonmr1.currentTitle == "X" 
    { 
     Winner.text = "Player X wins!" 
    } 
    else if Buttonbl1.currentTitle == "X" && Buttonbm1.currentTitle == "X" && Buttonbr1.currentTitle == "X" 
    { 
     Winner.text = "Player X wins!" 
    } 
    else if Buttontl1.currentTitle == "X" && Buttonml1.currentTitle == "X" && Buttonbl1.currentTitle == "X" 
    { 
     Winner.text = "Player X wins!" 
    } 
    else if Buttontm1.currentTitle == "X" && Buttonm1.currentTitle == "X" && Buttonbm1.currentTitle == "X" 
    { 
     Winner.text = "Player X wins!" 
    } 
    else if Buttontr1.currentTitle == "X" && Buttonmr1.currentTitle == "X" && Buttonbr1.currentTitle == "X" 
    { 
     Winner.text = "Player X wins!" 
    } 
    else if Buttontl1.currentTitle == "X" && Buttonm1.currentTitle == "X" && Buttonbr1.currentTitle == "X" 
    { 
     Winner.text = "Player X wins!" 
    } 
    else if Buttontr1.currentTitle == "X" && Buttonm.currentTitle == "X" && Buttonbl1.currentTitle == "X" 
    { 
     Winner.text = "Player X wins!" 
    } 
// Winner X 

// Winner O 
    if Buttontl1.currentTitle == "O" && Buttontm1.currentTitle == "O" && Buttontr1.currentTitle == "O" 
    { 
     Winner.text = "Player O wins!" 
    } 
    else if Buttonml1.currentTitle == "O" && Buttonm1.currentTitle == "O" && Buttonmr1.currentTitle == "O" 
    { 
     Winner.text = "Player O wins!" 
    } 
    else if Buttonbl1.currentTitle == "O" && Buttonbm1.currentTitle == "O" && Buttonbr1.currentTitle == "O" 
    { 
     Winner.text = "Player O wins!" 
    } 
    else if Buttontl1.currentTitle == "O" && Buttonml1.currentTitle == "O" && Buttonbl1.currentTitle == "O" 
    { 
     Winner.text = "Player O wins!" 
    } 
    else if Buttontm1.currentTitle == "O" && Buttonm1.currentTitle == "O" && Buttonbm1.currentTitle == "O" 
    { 
     Winner.text = "Player O wins!" 
    } 
    else if Buttontr1.currentTitle == "O" && Buttonmr1.currentTitle == "O" && Buttonbr1.currentTitle == "O" 
    { 
     Winner.text = "Player O wins!" 
    } 
    else if Buttontl1.currentTitle == "O" && Buttonm1.currentTitle == "O" && Buttonbr1.currentTitle == "O" 
    { 
     Winner.text = "Player O wins!" 
    } 
    else if Buttontr1.currentTitle == "O" && Buttonm.currentTitle == "O" && Buttonbl1.currentTitle == "O" 
    { 
     Winner.text = "Player O wins!" 
    } 
// Winner O 

以下是声明：

@IBOutlet weak var Winner: UILabel! 

//Buttons 
@IBAction func Buttonbr(_ sender: Any) { 
} 
@IBOutlet weak var Buttonbr1: UIButton! 

@IBAction func Buttonbm(_ sender: Any) { 
} 
@IBOutlet weak var Buttonbm1: UIButton! 

@IBAction func Buttonbl(_ sender: Any) { 
} 
@IBOutlet weak var Buttonbl1: UIButton! 

@IBAction func Buttonmr(_ sender: Any) { 
} 
@IBOutlet weak var Buttonmr1: UIButton! 

@IBAction func Buttonm(_ sender: Any) { 
} 
@IBOutlet weak var Buttonm1: UIButton! 

@IBAction func Buttonml(_ sender: Any) { 
} 
@IBOutlet weak var Buttonml1: UIButton! 

@IBAction func Buttontr(_ sender: Any) { 
} 
@IBOutlet weak var Buttontr1: UIButton! 

@IBAction func Buttontm(_ sender: Any) { 
} 
@IBOutlet weak var Buttontm1: UIButton! 

@IBAction func Buttontl(_ sender: Any) { 
} 
@IBOutlet weak var Buttontl1: UIButton! 

Answer 1

你有一个错字：

else if Buttontr1.currentTitle == "O" && Buttonm.currentTitle == "O" && Buttonbl1.currentTitle == "O" 

具体来说，在这里：

Buttonm.currentTitle 

要解决此问题，请用您想要参考的变量的正确名称替换Buttonm（Buttonm1？）。

Buttonm定义为：

@IBAction func Buttonm(_ sender: Any) { 

...因此你的错误。