PHP自动阵列与正则表达式

Question

例外，新的生产线，我有文字变量：

$string = "foo 
    bar 
    cel 
    [except this title:] 
    one 
    naa 
"; 

，我需要将其转换为数组，但排除“[除了这个称号：]”：

Array 
     (
      [0] => foo 
      [1] => bar 
      [2] => cel 
      [3] => one 
      [4] => naa 
     ) 

我有试试这个代码：

$string = "foo 
    bar 
    [except this title:] 
    cel 
    one 
    naa"; 
$array = preg_split("/(\r\n|\n|\r)/", $string); 
$i = 1; 
foreach($array as $key => $value) { 
    echo "$i: $value <br>"; 
    $i++; 
} 

但显示：

1: foo 
2: bar 
3: [except this title:] 
4: cel 
5: one 
6: naa 

我要显示这样的代码：

1.foo 
2.bar 

except this title: 
3.cel 
4.one 
5.naa 

在此先感谢。

Answer 1

如何：

$string = "foo 
    bar 
    [except this title:] 
    cel 
    one 
    naa"; 
$array = preg_split("/[\r\n]+/", $string); 
$i = 1; 
foreach($array as $key => $value) { 
    $value = trim($value); 
    if ($value[0] == '[') { 
     $value = preg_replace('/[[\]]/', '', $value); 
     echo "<br>$value<br>"; 
    } else { 
     echo "$i.$value<br>"; 
     $i++; 
    } 
} 

输出：

1.foo 
2.bar 

except this title: 
3.cel 
4.one 
5.naa 

Answer 2

$array = explode("\n", $string); 
foreach($array as $key => $value) { 
    $value = trim($value); 
    if ($value[0] != "[") { 
    echo ($key+1).": $value <br>\n"; 
    } 
} 

Answer 3

$a = preg_split("~[\n]+\s*~", $string, -1, PREG_SPLIT_NO_EMPTY); 
$i = 0; 
foreach ($a as $v) { 
    $v = trim($v); 
    if ($v[0] == "[") { 
     echo trim($v, "\x5b..\x5d") ."\n"; 
     continue; 
    } 
    echo (++$i) .".$v\n"; 
} 

的;

 
1.foo 
2.bar 
3.cel 
except this title: 
4.one 
5.naa