我的表单没有提交,我的数据库插入类的作品,我已经测试。但是我的表单似乎不想提交或发布我的表单中的值。有没有我遗漏的东西?表单不提交HTML php
<form name="form1" method="post" action="sub_newsletter.php" enctype="multipart/form-data">
<table border="0" cellspacing="0" cellpadding="0">
<tr>
<td colspan="2">Newsletter</td>
</tr>
<tr>
<td>Name : </td>
<td><input name="name" type="text"></td>
</tr>
<tr>
<td>Email : </td>
<td><input name="email" type="text"></td>
</tr>
<tr>
<td> <input type="text" name="check_spam" id="check_spam" size="30" style="display:none;" /> </td>
<td> </td>
</tr>
<tr>
<td colspan="2" align="center"><input type="image" name="submit" src="images/sub.jpg" style="width:180px; height:70px;"></td>
</tr>
</form>
</table>
我提交脚本
<?php
include('includes/database.php');
include('includes/settings.php');
include('includes/newsletter.php');
if (isset($_POST['submit'])){
//to check if posting
echo $username=rtrim($_POST['name']);
echo $myemail=rtrim($_POST['email']);
//
$check=$_POST['check_spam'];
if(!empty($check)){ echo "You are spam"; } else{
$username=rtrim($_POST['name']);
$myemail=rtrim($_POST['email']);
$news = new Newsletter();
$new->first_name=$username;
$new->email=$myemail;
$new->create();
echo "<script>alert(\"Thank you for your subscription\"); </script>";
echo "<script>window.location.replace(\"index.html\"); </script>";
}
}
?>
其中? – Vimalnath 2013-03-09 18:07:10
这是因为你正在使用和图像按钮 - “'用一个提交按钮替换它 - ''并且简单地使用CSS来增强它的外观。一个图像按钮在你点击它时会传递X和Y坐标,并且你提到的条件 - 'if(isset($ _ POST ['submit'])){}'永远不会被满足。 – Lion 2013-03-09 18:11:54