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这是原来的MySQL查询:MySQL查询添加到PHP文件
UPDATE jos_bully_table AS jbt1
INNER
JOIN (SELECT jbt2.bully_concat_name,
COUNT(*) AS b_name_count
FROM jos_bully_table AS jbt2
GROUP
BY jbt2.bully_concat_name
) AS jbt3
ON jbt3.bully_concat_name = jbt1.bully_concat_name
SET jbt1.b_name_count = jbt3.b_name_count
;
它从phpMyAdmin的运行时的伟大工程。我点击创建PHP代码,这会产生:
$sql = "UPDATE jos_bully_table AS jbt1\n"
. " INNER\n"
. " JOIN (SELECT jbt2.bully_concat_name,\n"
. " COUNT(*) AS b_name_count\n"
. " FROM jos_bully_table AS jbt2\n"
. " GROUP\n"
. " BY jbt2.bully_concat_name\n"
. ") AS jbt3\n"
. " ON jbt3.bully_concat_name = jbt1.bully_concat_name\n"
. " SET jbt1.b_name_count = jbt3.b_name_count\n"
. "";
我试图运行从一个php文件相同的查询,但是该数据库没有更新。
这里是我的PHP文件:
<?php
$database = "xxxxxxxxx" ;
$username = "xxxxxxxxx" ;
$password = "xxxxxxxxx" ;
mysql_connect(localhost,$username,$password);
@mysql_select_db($database) or die("Unable to select database");
mysql_query($sql);
$sql = "UPDATE jos_bully_table AS jbt1\n"
. " INNER\n"
. " JOIN (SELECT jbt2.bully_concat_name,\n"
. " COUNT(*) AS b_name_count\n"
. " FROM jos_bully_table AS jbt2\n"
. " GROUP\n"
. " BY jbt2.bully_concat_name\n"
. ") AS jbt3\n"
. " ON jbt3.bully_concat_name = jbt1.bully_concat_name\n"
. " SET jbt1.b_name_count = jbt3.b_name_count\n"
. "";
echo "<!-- SQL Error ".mysql_error()." -->";
?>
有什么不对呢?