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正如标题所说,我想在我的应用程序的alertDialog中创建一个按钮,转到某个URI,并且我在想我该怎么做?alertDialog按钮转到URI
继承人和代码的摘录:
// Add a neutral button to the alert box AND assign a listener for said button...
alertbox.setNeutralButton("Ok", new DialogInterface.OnClickListener(){
// click listener for box
public void onClick(DialogInterface arg0, int arg1){
// Button was clicked!!
Toast.makeText(getApplicationContext(), "Dialog closed successfully!", Toast.LENGTH_LONG).show();
}
});
// Add a Forums button to take user to forums...
alertbox.setPositiveButton("Forums", new DialogInterface.OnClickListener(){
//listener for button
public void onClick(DialogInterface arg0, int arg1){
// Button Pressed!
Toast.makeText(getApplicationContext(), "Oops...this button is broke!", Toast.LENGTH_LONG).show();
}
});
// show it!!!
alertbox.show();
,而不是使显示敬酒信息称该按钮破产了,其实我是想它启动浏览器并把用户带到一个URI。
必须有一种方法...
想法?
谢谢!在onClick()
处理
与更多的代码更新..
,完美的工作!非常感谢! – death2all110