PHP脚本返回“file_get_contents

Question

我正在我的本地Windows 8开发机器上建立一个站点（使用wamp）。我有一个PHP脚本，假设从我的服务器上的目录中获取映像文件，并将它们上传到基于WordPress的当我在目录中有一个文件时工作正常当我修改从目录上传多个文件的代码时，只有一个图像被上传，并且我得到一个错误说：file_get_content(/path/to/directory/): failed ot open stream. Permission denied in /path/to/script/这是我接收到的错误的图像http://i.imgur.com/rRvxKa0.jpg

下面是目录中的一个文件工作代码：

global $post; 

    $rpcurl = get_bloginfo('url') . "/xmlrpc.php"; 

    $username = 'admin'; 
    $password = 'admin'; 
    $blogid = $post->ID; //Post ID 

    $post_idn = get_post_meta($post->ID, 'VIN', true); 

    $post_dir = dirname(get_template_directory()) . "/" . $post_idn; 

    $file = file_get_contents($post_dir . "/file.jpg"); 

    $filetype = "image/jpeg"; 

    $filename = "remote_filename.jpg"; 

    xmlrpc_set_type($file,'base64'); // <-- required! 
    $params = array($blogid,$username,$password, 
       array('name'=>$filename,'type'=>$filetype,'bits'=>$file,'overwrite'=>false)); 
    $request = xmlrpc_encode_request('wp.uploadFile',$params); 

    function go($request,$rpcurl){ 
     $ch = curl_init(); 
     curl_setopt($ch,CURLOPT_POST,1); 
     curl_setopt($ch,CURLOPT_URL,$rpcurl); 
     curl_setopt($ch,CURLOPT_POSTFIELDS,$request); 
     curl_setopt($ch,CURLOPT_RETURNTRANSFER,1); 
     $result = curl_exec($ch); 
    } 

    $result = go($request,$rpcurl); 
    print_r($result); 

这是假设上传多个图像的代码。

$rpcurl = get_bloginfo('url') . "/xmlrpc.php"; 

    echo $rpcurl; 

    $username = 'admin'; 
    $password = 'admin'; 
    $blogid = $post->ID; //Post ID 

    echo $blogid; 

    $post_idn = get_post_meta($post->ID, 'VIN', true); 

    echo "<h1>" . $post_idn ."</h1>"; 

    $post_dir = dirname(get_template_directory()) . "/" . $post_idn; 

    $fileslist = scandir($post_dir); 

    foreach ($fileslist as $file) { 

     $file = file_get_contents($post_dir . "/" . $file); 

     $filetype = "image/jpeg"; 

     $filename = "remote_filename.jpg"; 

     xmlrpc_set_type($file,'base64'); // <-- required! 
     $params = array($blogid,$username,$password, 
        array('name'=>$filename,'type'=>$filetype,'bits'=>$file,'overwrite'=>false)); 
     $request = xmlrpc_encode_request('wp.uploadFile',$params); 
    } 

     function go($request,$rpcurl){ 
      $ch = curl_init(); 
      curl_setopt($ch,CURLOPT_POST,1); 
      curl_setopt($ch,CURLOPT_URL,$rpcurl); 
      curl_setopt($ch,CURLOPT_POSTFIELDS,$request); 
      curl_setopt($ch,CURLOPT_RETURNTRANSFER,1); 
      $result = curl_exec($ch); 
     } 

     $result = go($request,$rpcurl); 
     print_r($result); 

Answer 1

scandir will return . and .., along with all real files and subdirectories。你需要过滤那些出：

foreach ($fileslist as $file) { 
    if($file === '.' || $file === '..') { 
     continue; 
    } 

    $file = file_get_contents($post_dir . "/" . $file); 

    $filetype = "image/jpeg"; 

    $filename = "remote_filename.jpg"; 

    xmlrpc_set_type($file,'base64'); // <-- required! 
    $params = array($blogid,$username,$password, 
       array('name'=>$filename,'type'=>$filetype,'bits'=>$file,'overwrite'=>false)); 
    $request = xmlrpc_encode_request('wp.uploadFile',$params); 
} 

尖端过这里的错误消息：file_get_contents(/path/to/directory/): failed to open stream. Permission denied in /path/to/script/如果$file是一个真实的文件，你会看到/path/to/directory/somefile.extension，不只是/path/to/directory/。

另外，您将为每个上传的文件指定与该行相同的文件名：$filename = "remote_filename.jpg";因此，无论上传多少个文件，最后只留下一个（第一个文件，因为'overwrite'=>false）。