蟒蛇计数复制列表

Question

我有这个名单：

['Boston Americans', 'New York Giants', 'Chicago White Sox', 'Chicago Cubs', 'Chicago Cubs', 'Pittsburgh Pirates', 'Philadelphia Athletics', 'Philadelphia Athletics', 'Boston Red Sox', 'Philadelphia Athletics', 'Boston Braves', 'Boston Red Sox', 'Boston Red Sox', 'Chicago White Sox', 'Boston Red Sox', 'Cincinnati Reds', 'Cleveland Indians', 'New York Giants', 'New York Giants', 'New York Yankees', 'Washington Senators', 'Pittsburgh Pirates', 'St. Louis Cardinals', 'New York Yankees', 'New York Yankees', 'Philadelphia Athletics', 'Philadelphia Athletics', 'St. Louis Cardinals', 'New York Yankees', 'New York Giants', 'St. Louis Cardinals', 'Detroit Tigers', 'New York Yankees', 'New York Yankees', 'New York Yankees', 'New York Yankees', 'Cincinnati Reds', 'New York Yankees', 'St. Louis Cardinals', 'New York Yankees', 'St. Louis Cardinals', 'Detroit Tigers', 'St. Louis Cardinals', 'New York Yankees', 'Cleveland Indians', 'New York Yankees', 'New York Yankees'] 

我怎样才能从这个名单删除重复的不使用计数，追加或set方法或进口？

或者我真正想要的是：我如何可以反过来说，名单打印出来是这样的：

Boston Americans 5 
New York Giants 2 
team_name number_of_duplicates 
team_name number_of_duplicates 
team_name number_of_duplicates 

Answer 1

l =['Boston Americans', 'New York Giants', 'Chicago White Sox', 'Chicago Cubs', 'Chicago Cubs', 'Pittsburgh Pirates', 'Philadelphia Athletics', 'Philadelphia Athletics', 'Boston Red Sox', 'Philadelphia Athletics', 'Boston Braves', 'Boston Red Sox', 'Boston Red Sox', 'Chicago White Sox', 'Boston Red Sox', 'Cincinnati Reds', 'Cleveland Indians', 'New York Giants', 'New York Giants', 'New York Yankees', 'Washington Senators', 'Pittsburgh Pirates', 'St. Louis Cardinals', 'New York Yankees', 'New York Yankees', 'Philadelphia Athletics', 'Philadelphia Athletics', 'St. Louis Cardinals', 'New York Yankees', 'New York Giants', 'St. Louis Cardinals', 'Detroit Tigers', 'New York Yankees', 'New York Yankees', 'New York Yankees', 'New York Yankees', 'Cincinnati Reds', 'New York Yankees', 'St. Louis Cardinals', 'New York Yankees', 'St. Louis Cardinals', 'Detroit Tigers', 'St. Louis Cardinals', 'New York Yankees', 'Cleveland Indians', 'New York Yankees', 'New York Yankees'] 

for team in [ele for ind, ele in enumerate(l,1) if ele not in l[ind:]]: 
    print("{} {}".format(team,l.count(team))) 
Boston Americans 1 
Chicago Cubs 2 
Boston Braves 1 
Chicago White Sox 2 
Boston Red Sox 4 
Washington Senators 1 
Pittsburgh Pirates 2 
Philadelphia Athletics 5 
New York Giants 4 
Cincinnati Reds 2 
Detroit Tigers 2 
St. Louis Cardinals 6 
Cleveland Indians 2 
New York Yankees 13 

不使用list.count可言：

for team in [ele for ind, ele in enumerate(l,1) if ele not in l[ind:]]: 
    count = 0 
    for ele in l: 
     if team == ele: 
      count += 1 
    print("{} {}".format(team,count)) 
    count = 0 

Boston Americans 1 
Chicago Cubs 2 
Boston Braves 1 
Chicago White Sox 2 
Boston Red Sox 4 
Washington Senators 1 
Pittsburgh Pirates 2 
Philadelphia Athletics 5 
New York Giants 4 
Cincinnati Reds 2 
Detroit Tigers 2 
St. Louis Cardinals 6 
Cleveland Indians 2 
New York Yankees 13 

你没有说你是否可以使用的字典或并非如此：

d = {} 

for team in l: 
    # if we have not seen team before, create k/v pairing 
    # setting value to 0, if team already in dict this does nothing 
    d.setdefault(team,0) 
    # increase the count for the team 
    d[team] += 1 
for team, count in d.items(): 
    print("{} {}".format(team,count)) 

Chicago White Sox 2 
New York Giants 4 
Cincinnati Reds 2 
Boston Red Sox 4 
New York Yankees 13 
Philadelphia Athletics 5 
Pittsburgh Pirates 2 
St. Louis Cardinals 6 
Washington Senators 1 
Boston Braves 1 
Boston Americans 1 
Cleveland Indians 2 
Detroit Tigers 2 
Chicago Cubs 2 

Answer 2

你可以做新的列表，例如

l = ['Boston Americans', 'New York Giants', 'Chicago White Sox', 'Chicago Cubs', 'Chicago Cubs', 'Pittsburgh Pirates', 'Philadelphia Athletics', 'Philadelphia Athletics', 'Boston Red Sox', 'Philadelphia Athletics', 'Boston Braves', 'Boston Red Sox', 'Boston Red Sox', 'Chicago White Sox', 'Boston Red Sox', 'Cincinnati Reds', 'Cleveland Indians', 'New York Giants', 'New York Giants', 'New York Yankees', 'Washington Senators', 'Pittsburgh Pirates', 'St. Louis Cardinals', 'New York Yankees', 'New York Yankees', 'Philadelphia Athletics', 'Philadelphia Athletics', 'St. Louis Cardinals', 'New York Yankees', 'New York Giants', 'St. Louis Cardinals', 'Detroit Tigers', 'New York Yankees', 'New York Yankees', 'New York Yankees', 'New York Yankees', 'Cincinnati Reds', 'New York Yankees', 'St. Louis Cardinals', 'New York Yankees', 'St. Louis Cardinals', 'Detroit Tigers', 'St. Louis Cardinals', 'New York Yankees', 'Cleveland Indians', 'New York Yankees', 'New York Yankees'] 
l2 = [] 
for v in l: 
    if v not in l2: 
     l2 = l2 + [v] 

print(l2) 

给出：

['Boston Americans', 'New York Giants', 'Chicago White Sox', 'Chicago Cubs', 'Pittsburgh Pirates', 'Philadelphia Athletics', 'Boston Red Sox', 'Boston Braves', 'Cincinnati Reds', 'Cleveland Indians', 'New York Yankees', 'Washington Senators', 'St. Louis Cardinals', 'Detroit Tigers'] 

Answer 3

list=['Boston Americans', 'New York Giants', 'Chicago White Sox', 'Chicago Cubs', 'Chicago Cubs', 'Pittsburgh Pirates', 'Philadelphia Athletics', 'Philadelphia Athletics', 'Boston Red Sox', 'Philadelphia Athletics', 'Boston Braves', 'Boston Red Sox', 'Boston Red Sox', 'Chicago White Sox', 'Boston Red Sox', 'Cincinnati Reds', 'Cleveland Indians', 'New York Giants', 'New York Giants', 'New York Yankees', 'Washington Senators', 'Pittsburgh Pirates', 'St. Louis Cardinals', 'New York Yankees', 'New York Yankees', 'Philadelphia Athletics', 'Philadelphia Athletics', 'St. Louis Cardinals', 'New York Yankees', 'New York Giants', 'St. Louis Cardinals', 'Detroit Tigers', 'New York Yankees', 'New York Yankees', 'New York Yankees', 'New York Yankees', 'Cincinnati Reds', 'New York Yankees', 'St. Louis Cardinals', 'New York Yankees', 'St. Louis Cardinals', 'Detroit Tigers', 'St. Louis Cardinals', 'New York Yankees', 'Cleveland Indians', 'New York Yankees', 'New York Yankees'] 
list1=[] 
list2=[] 
for x in list: 
    if not x in list1: 
     list1.append(x) 
    if x in list1: 
     list2.append(x) 
list2.sort() 
for num,og in enumerate(list2,1): 
    print (num,og) 

Answer 4

players = ['Boston Americans', 'New York Giants', 'Chicago White Sox', 'Chicago Cubs', 'Chicago Cubs', 'Pittsburgh Pirates', 'Philadelphia Athletics', 'Philadelphia Athletics', 'Boston Red Sox', 'Philadelphia Athletics', 'Boston Braves', 'Boston Red Sox', 'Boston Red Sox', 'Chicago White Sox', 'Boston Red Sox', 'Cincinnati Reds', 'Cleveland Indians', 'New York Giants', 'New York Giants', 'New York Yankees', 'Washington Senators', 'Pittsburgh Pirates', 'St. Louis Cardinals', 'New York Yankees', 'New York Yankees', 'Philadelphia Athletics', 'Philadelphia Athletics', 'St. Louis Cardinals', 'New York Yankees', 'New York Giants', 'St. Louis Cardinals', 'Detroit Tigers', 'New York Yankees', 'New York Yankees', 'New York Yankees', 'New York Yankees', 'Cincinnati Reds', 'New York Yankees', 'St. Louis Cardinals', 'New York Yankees', 'St. Louis Cardinals', 'Detroit Tigers', 'St. Louis Cardinals', 'New York Yankees', 'Cleveland Indians', 'New York Yankees', 'New York Yankees'] 

players_details, players_name = [], [] 
for each_player in players: 
    if not(each_player in players_name): 
     players_name = players_name + [each_player] 
     players_details = players_details + [[each_player, 1]] 
    else: 
     for index in range(len(players_details)): 
      if players_details[index][0] == each_player: 
       players_details[index][1] = players_details[index][1]+1 

for each in players_details: 
    print '{} : {}'.format(*each) 

结果：

Boston Americans : 1 
New York Giants : 4 
Chicago White Sox : 2 
Chicago Cubs : 2 
Pittsburgh Pirates : 2 
Philadelphia Athletics : 5 
Boston Red Sox : 4 
Boston Braves : 1 
Cincinnati Reds : 2 
Cleveland Indians : 2 
New York Yankees : 13 
Washington Senators : 1 
St. Louis Cardinals : 6 
Detroit Tigers : 2 

Answer 5

要算多少每个条目的还有在列表中你可以使用Counter类collections模块：

l =['Boston Americans', 'New York Giants', 'Chicago White Sox', 'Chicago Cubs', 'Chicago Cubs', 'Pittsburgh Pirates', 'Philadelphia Athletics', 'Philadelphia Athletics', 'Boston Red Sox', 'Philadelphia Athletics', 'Boston Braves', 'Boston Red Sox', 'Boston Red Sox', 'Chicago White Sox', 'Boston Red Sox', 'Cincinnati Reds', 'Cleveland Indians', 'New York Giants', 'New York Giants', 'New York Yankees', 'Washington Senators', 'Pittsburgh Pirates', 'St. Louis Cardinals', 'New York Yankees', 'New York Yankees', 'Philadelphia Athletics', 'Philadelphia Athletics', 'St. Louis Cardinals', 'New York Yankees', 'New York Giants', 'St. Louis Cardinals', 'Detroit Tigers', 'New York Yankees', 'New York Yankees', 'New York Yankees', 'New York Yankees', 'Cincinnati Reds', 'New York Yankees', 'St. Louis Cardinals', 'New York Yankees', 'St. Louis Cardinals', 'Detroit Tigers', 'St. Louis Cardinals', 'New York Yankees', 'Cleveland Indians', 'New York Yankees', 'New York Yankees'] 

from collections import Counter 
c = Counter(l) 
print(c) 

c然后一个Counter对象，该对象为每个不同的条目/键保存列表中出现的次数。由于Counter源自dict，因此您可以像访问其他任何字典一样访问它。

Counter({'New York Yankees': 13, 'St. Louis Cardinals': 6, 'Philadelphia Athletics': 5, 'New York Giants': 4, 'Boston Red Sox': 4, 'Chicago White Sox': 2, 'Pittsburgh Pirates': 2, 'Detroit Tigers': 2, 'Cincinnati Reds': 2, 'Cleveland Indians': 2, 'Chicago Cubs': 2, 'Boston Americans': 1, 'Boston Braves': 1, 'Washington Senators': 1})