WCF的REST类型的WS POST方法和HTML表单

Question

我有IIS发布简单的.NET RESTful Web服务：

[OperationContract] 
    [WebInvoke(Method = "GET", ResponseFormat = WebMessageFormat.Json, UriTemplate = "formTestGET?firstInput={firstInput}&socondInput={socondInput}")] 
    string formTestGET(string firstInput, string socondInput); 

    [OperationContract] 
    [WebInvoke(Method = "POST", ResponseFormat = WebMessageFormat.Json, UriTemplate = "formTestPOST")] 
    string formTestPOST(string testInput); 

的方法实现：

public string formTestGET(string firstInput, string socondInput) 
     { 
     try 
      { 
      return "First Input value: " + firstInput + " Second Input value: " + socondInput; 
      } 
     catch (Exception e) 
      { 
      return e.Message; 
      } 
     } 

    public string formTestPOST(string testInput) 
     { 
     try 
      { 
      return "Post paramether value: " + testInput; 
      } 
     catch (Exception e) 
      { 
      return e.Message; 
      } 
     } 

我的HTML表单：

<form method="post" action="http://localhost/HTML5RestfulService/Service1.svc/formTestPOST"> 
     <fieldset> 
     <legend>Form Post Request</legend> 
      <input name="testInput"/> 
      <button>Make Post Request</button> 
     </fieldset> 
    </form> 

我只想通过html表单来使用此服务。我的POST方法有问题。当我使用Ajax（从java脚本）调用它时，它工作正常，但通过表单我无法获得响应。 我收到“400错误请求”作为错误。

当我想通过FORM调用它时，我应该不同地配置我的WS吗？

请提供任何建议。

Answer 1

如果你想从没有ECMAScript（JavaScript），Silverlight或Flash的基本表单中调用WCF服务，那么我认为你应该遵循Cheng先生的建议，并将formTestPOST操作的输入参数更改为单个Stream参数。

请参见下面的代码了解更多详情：

// File: IService1.cs 
//  (Based on work by Milos, Shawn Eary, Steven Cheng, and 
//  Web Community) 
// 
// References 
// [1] - Cheng, Steven (MSFT); Bill2010 
//  How would I do the following form POST with WCF REST? 
//  MSDN Forums: August 12, 2010 
//  http://social.msdn.microsoft.com/Forums/vstudio/en-US/dde73561-29c0-4c34-b18a-990ae114b92c/how-would-i-do-the-following-form-post-with-wcf-rest 
//  [Cited: September 27, 2013] 
using System.ServiceModel; 
using System.ServiceModel.Web; 
using System.IO; 

[ServiceContract] 
public interface IService1 
{ 
    // To post a basic HTML Form to a WCF Operation, I *think* Mr. Cheng 
    // of Microsoft suggests that users put WCF into "Raw Data Transfer" 
    // Mode by replacing all input parameters with a single Stream [1] 
    [OperationContract] 
    [WebInvoke(Method = "POST", ResponseFormat = WebMessageFormat.Json, UriTemplate = "formTestPOST")] 
    string formTestPOST(Stream testInput); 
} 

和

// File: Service1.cs 
//  (Based on work by: Milos; Shawn Eary; all those listed 
//  in the References Section below; and, the Web Community) 
// 
// References 
// [1] - Brian; Coderer; Kopp, Darren; James; user1749204  
//  How do you get a string from a MemoryStream? 
//  Stack Overflow: September 29, 2008 
//  http://stackoverflow.com/questions/78181/how-do-you-get-a-string-from-a-memorystream 
//  [Cited: September 27, 2013] 
// 
// [2] - Atlas, Mike; HaggleLad; Gravell, Marc 
//  Parsing “multipart/form-data” in .NET/C# 
//  Stack Overflow: November 11, 2009 
//  http://stackoverflow.com/questions/1716868/parsing-multipart-form-data-in-net-c 
//  [Cited: September 27, 2013] 
// 
// [3] - antscode 
//  Multipart Form Data Parser 
//  CodePlex: 2009-2012 
//  http://multipartparser.codeplex.com/SourceControl/list/changesets 
//  [Cited: September 27, 2013] 
// 
// [4] - Polidori, Lorenzo; Ed. S.; Woods, Jake 
//  Uploading file from Flex to WCF REST Stream issues (how to decode multipart form post in REST WS) 
//  Stack Overflow: January 20, 2012 
//  http://stackoverflow.com/questions/5423031/uploading-file-from-flex-to-wcf-rest-stream-issues-how-to-decode-multipart-form 
//  [Cited: September 27, 2013] 
using System; 
using System.IO; 
using System.Web; 

public class Service1 : IService1 
{ 
    public string formTestPOST(Stream testInput) 
    { 
     // Get the post data out of the Stream testInput 
     // Now that your form sucessfully fired this operation, you 
     // can use Brian's technique mentioned at [1] to convert the 
     // stream into a string 
     StreamReader someReader = new StreamReader(testInput); 
     String theInput = someReader.ReadToEnd(); 

     // Unfortunately, various places on the internet seem to 
     // indicate that data that you now have in your string 
     // theInput is multipart form data. If you were willing 
     // to use ASP.NET Compatibility Mode in your Interface, 
     // then you could have used the trick here mentioned by 
     // Mike Atlas and Mark Gravel in [2] but let's assume 
     // you cannot use compatibilty mode. Then you might 
     // try a multipart parser like the one written by antscode 
     // at [3] or you can just do what I did and guess your 
     // way through. Since you have a simple form, you can 
     // just guess your way through the parsing by replacing 
     // "testInput" with nothing and UrlDecoding what is left. 
     // That won't work on more complex forms but it works on 
     // this example. You get some more backround on this 
     // and why UrlDecode is necessary at [4] 
     theInput = theInput.Replace("testInput=", ""); 
     theInput = HttpUtility.UrlDecode(theInput); 
     return "Post paramether value: " + theInput; 
    } 
}