所以我需要知道的是,我怎样才能一次连接两个数据库。 我正在做的是从一个数据库表中获取一些信息并将其传送到另一个数据库。OOPHP连接两个数据库
我试过以下。
$db1 = mysql_connect(...);
$db2 = mysql_connect(...);
mysql_query('SELECT ...', $db1);
mysql_query('INSERT ...', $db2);
看的文档http://www.php.net/mysql_connect和:
public function sitelistingcron()
{
$sqlk = mysql_query("SELECT * FROM customer_detail WHERE approvedforsite = 2 OR approvedforsite = 3");
include_once('database2.php');
$fet = new Dbase();
$fet->Connect();
$fet->DB();
while($row = mysql_fetch_array($sqlk)){
//ADD
$this->customer_id = $row['customer_id'];
$this->tradingname = $row['TradingName'];
$this->phone = $row['Phone'];
$this->street = $row['Street'];
$this->city = $row['City'];
$this->state = $row['State'];
$this->postcode = $row['PostCode'];
$this->approved = $row['approvedforsite'];
$this->description = $row['Description'];
if($this->approved = 2)
{
$sqk = mysql_query("INSERT INTO approved_business_info (id, tradingname, phonenumber, street, postcode, suburb, discription) VALUES ({$this->customer_id}, '{$this->tradingname}', '{$this->phone}', '{$this->street}', '{$this->city}', '{$this->postcode}', '{$this->description}') ON DUPLICATE KEY UPDATE id = {$this->customer_id}, tradingname ='{$this->tradingname}', phonenumber ='{$this->phone}', street = '{$this->street}', postcode = '{$this->postcode}', suburb = '{$this->city}', discription = '{$this->discription}'") or mysql_error();
print "INSERT INTO approved_business_info (id, tradingname, phonenumber, street, postcode, suburb, discription) VALUES ({$this->customer_id}, '{$this->tradingname}', '{$this->phone}', '{$this->street}', '{$this->city}', '{$this->postcode}', '{$this->description}') ON DUPLICATE KEY UPDATE id = {$this->customer_id}, tradingname ='{$this->tradingname}', phonenumber ='{$this->phone}', street = '{$this->street}', postcode = '{$this->postcode}', suburb = '{$this->city}', discription = '{$this->discription}'";
}
//REMOVE
if($this->approved = 3)
{
$sqk = mysql_query("DELETE FROM `approved_business_info` WHERE id = {$this->customer_id}");
}
}
}
'$ result = sql_query($ conn1,$ sql1); $ sql2 = makeInsertStatements($ result); sql_update($ conn2,$ sql2);' – bdares 2011-12-20 01:54:18
*你是如何连接到数据库的?只要这样做两次...? – deceze 2011-12-20 01:56:45
请停止使用古老的'mysql_ *'函数,并学习使用[PDO](http://php.net/pdo)或[MySQLi](http://php.net/mysqli)以及准备好的语句。 – 2011-12-20 05:21:02