此代码生成所需的数据串的3D名单。
a = (0, 0), (2, 0), (0, 2), (2, 2)
b = 10, 11, 12
result = [
[
[str(i + j) for j in b] + [str(u) + str(v+i)] for i in range(6)
] for u, v in a
]
# Display the resulting list in a relatively compact way
for row in result:
print([' '.join(u) for u in row])
输出
['10 11 12 00', '11 12 13 01', '12 13 14 02', '13 14 15 03', '14 15 16 04', '15 16 17 05']
['10 11 12 20', '11 12 13 21', '12 13 14 22', '13 14 15 23', '14 15 16 24', '15 16 17 25']
['10 11 12 02', '11 12 13 03', '12 13 14 04', '13 14 15 05', '14 15 16 06', '15 16 17 07']
['10 11 12 22', '11 12 13 23', '12 13 14 24', '13 14 15 25', '14 15 16 26', '15 16 17 27']
如果这些对实际上应该是对的整数,我们需要一个稍微不同的策略:
from pprint import pprint
a = (0, 0), (2, 0), (0, 2), (2, 2)
b = 10, 11, 12
result = [
[
[divmod(i + j, 10) for j in b] + [(u, v+i)] for i in range(6)
] for u, v in a
]
pprint(result)
输出
[[[(1, 0), (1, 1), (1, 2), (0, 0)],
[(1, 1), (1, 2), (1, 3), (0, 1)],
[(1, 2), (1, 3), (1, 4), (0, 2)],
[(1, 3), (1, 4), (1, 5), (0, 3)],
[(1, 4), (1, 5), (1, 6), (0, 4)],
[(1, 5), (1, 6), (1, 7), (0, 5)]],
[[(1, 0), (1, 1), (1, 2), (2, 0)],
[(1, 1), (1, 2), (1, 3), (2, 1)],
[(1, 2), (1, 3), (1, 4), (2, 2)],
[(1, 3), (1, 4), (1, 5), (2, 3)],
[(1, 4), (1, 5), (1, 6), (2, 4)],
[(1, 5), (1, 6), (1, 7), (2, 5)]],
[[(1, 0), (1, 1), (1, 2), (0, 2)],
[(1, 1), (1, 2), (1, 3), (0, 3)],
[(1, 2), (1, 3), (1, 4), (0, 4)],
[(1, 3), (1, 4), (1, 5), (0, 5)],
[(1, 4), (1, 5), (1, 6), (0, 6)],
[(1, 5), (1, 6), (1, 7), (0, 7)]],
[[(1, 0), (1, 1), (1, 2), (2, 2)],
[(1, 1), (1, 2), (1, 3), (2, 3)],
[(1, 2), (1, 3), (1, 4), (2, 4)],
[(1, 3), (1, 4), (1, 5), (2, 5)],
[(1, 4), (1, 5), (1, 6), (2, 6)],
[(1, 5), (1, 6), (1, 7), (2, 7)]]]
下面是一个使用for循环,而不是嵌套列表理解的“传统”的第2解决方案的变化。希望阅读起来更容易一些。 :)
a = (0, 0), (2, 0), (0, 2), (2, 2)
b = 10, 11, 12
result = []
for u, v in a:
row = []
for i in range(6):
row.append([divmod(i + j, 10) for j in b] + [(u, v+i)])
result.append(row)
内置divmod
函数执行其参数除法和模量,所以,当a
和b
是整数divmod(a, b)
相当于a // b, a % b
。如果x
是一个两位整数`divmod(x,10)返回一个包含这两个数字的元组。
你可以展示你试过的东西,指出你遇到了哪些问题? – glibdud
是这功课吗? – RickyA
为什么最后2组('16 17 18 26'和'17 18 19 27')而不是('14 15 16 26'和'15 16 17 27')?这张表是什么样的数据结构?它只是一个字符串,还是应该是某种列表? –