2012-03-24 71 views
0

我有一个类中的2种功能的短信发送程序:开发使用Java Swing的

  1. login()登录到某个网站

  2. Send_Sms()发送短

这里我我正在考虑为这些功能添加2个线程,以便可以以开始发送的方式控制功能Send_Sms的功能login()之后的短信已成功完成,否则程序将无法工作。

这是我迄今所做的:

import java.io.BufferedWriter; 
import java.io.File; 
import java.io.FileWriter; 
import java.io.IOException; 
import java.io.Writer; 
import java.util.logging.Level; 
import java.util.logging.Logger; 


public class RunThreads extends Thread 
{ 
    public void Login(String username,String password) 
    { 
     try 
     { 
      // creates the batch file for Logging into abc.com server 
      Writer output = null; 
      String UserAgent = "Mozilla/5.0 (Windows NT 5.1;KM:10.0.2)"; 
      String postdata = "\"" + "username="+username+ "&password=" + password + "&button=Login" + "\""; 
      String MainStream = "c:\\wget.exe --output-document=login.html --user-agent=" + "\"" + UserAgent + "\"" + " --max-redirect=10 --cookies=on --keep-session-cookies --save-cookies=cookie.txt --post-data " + postdata + " http://www.abc.com/Login1.action;"; 
      File file = new File("login.bat"); 
      output = new BufferedWriter(new FileWriter(file)); 
      output.write(MainStream); 
      output.close(); 
      Runtime.getRuntime().exec("cmd /c start login.bat"); 
     } 
     catch (IOException ex) 
     { 
      Logger.getLogger(Save_Credentials.class.getName()).log(Level.SEVERE, null, ex); 
     } 
    } 
    public void SendSms(String mobno,String content) throws IOException 
    { 
       Writer output = null; 
       String UserAgent = "Mozilla/5.0 (Windows NT 5.1;KM:10.0.2)"; 
       String MainStream = "c:\\wget.exe --output-document=quicksms.html --user-agent=" + "\"" + UserAgent + "\"" + " --referer=http://www.abc.com/jsp/SMS.jsp --cookies=on --keep-session-cookies --load-cookies=cookie.txt --save-cookies=cookie.txt --post-data "+"\""+"&HiddenAction=instantsms&catnamedis=Birthday&Action=gstahsbdf5346g&chkall=on&MobNo="+mobno+"&textArea="+content+"\""+" http://www.abc.com/quicksms.action;"; 
       File file = new File("SendSms.bat"); 
       output = new BufferedWriter(new FileWriter(file)); 
       output.write(MainStream); 
       output.close(); 
       Runtime.getRuntime().exec("cmd /c start SendSms.bat"); 
    } 
    public static void main(String[] args) 
    { 


    } 
} 

回答

0

由于短信不能如果登录失败,发送你自己也说:

功能Send_Sms的exceution可以 的方式被控制,它在登录()成功完成 之后开始发送短信,否则程序将不起作用。

然后这两个任务是顺序耦合的,这意味着在不同线程上并行执行它们是没有意义的。只需在单个线程中按顺序执行它们即可。