2
夫特类别:访问参数化在ObjC类迅速方法
@objc public class XyzClass: NSObject {
var newlyVar = String()
func abcd (abc:String?, name:Int) {
}
func mymethod(userId:Int32?,startIndex:Int32?, lastIndex:Int32?, m_bankId:Int32?, m_DownPayment:Int32?,m_maxTenure:Int32?, m_salary:Int32?) {
}
func sampleMethod (userId:Int32,startIndex:Int32, lastIndex:Int32, m_bankId:Int32, m_DownPayment:Int32, m_maxTenure:Int32, m_salary:Int32, m_selfemployed:Int32, m_UAENational:Int32, complitionHandler: (_ success:Bool, _ loans:[Loan]) -> Void){
complitionHandler(true,[])
}
}
在ObjC类,我访问为:
LoanParser *lp = [[LoanParser alloc]init];
[lp abcdWithAbc:@"" name:32];
方法abcd
和可变newlyVar
是可访问的,但mymethod
和sampleMethod
ISN “T。
我在这里失踪的任何东西?
关注感觉是:Loan
类符合Mappable
协议
是有意义的。 ty buddy – preetam
更新的问题,增加了一个方法与completionhandler。请看看 – preetam
我没有问题从ObjC访问你的'sampleMethod'。虽然你拼写完成错了。 – Oskar