我想创建一个下拉列表,限制每页显示的图像数量,并允许用户决定要显示多少图片,默认情况下我已设置5我试图搜索净我不设法想出这里的解决方案是我试图下拉列表和php
<form action="image_search.php" name="formSize" method="post">
<span id="PageSize" style="color:Gray;">Page Size:</span>
<select name="pagesize">
<option selected="selected" value="5">5</option>
<option value="20">20</option>
<option value="50">50</option>
<option value="100">100</option>
</select>
<span id="Title" style="color:Gray;"></span>
</form>
<?php
include_once("includes/images.php");
$xml = simplexml_load_file("xml/images.xml"); //load the images
$page = 0;
if (isset($_POST['formSize']))
{
$varSize = $_POST['pagesize'];
}
$MAXELEMENTSPERPAGE = $varSize; //change this value to display how many elements per page you wish people to see
$maxPage = count($xml)/$MAXELEMENTSPERPAGE;
if(isset($_GET['page']))
{
$page = $_GET['page']; //if page is specif
}
?>
如果我删除$ varSize并与多家它的工作原理,但正如我得到这个错误 未定义的变量替换代码:varSize
你如何发布数据,formSize来自哪里? – Musa 2013-03-01 22:13:23