2016-11-23 61 views
0

我想教自己Python开始codeacademy的课程,到目前为止它一直好。然而,我在学生成为教师7/9时遇到了困难。我无法找到讨论这个问题的线索,但是如果我错过了一个,请随时让我知道。python codeacademy发送一封信

根据codeacademy我成功完成了这个练习,但我知道这段代码有问题。当我在repl.it中使用下面的代码时,get_average(student)会返回正确的值。我已经通过稍微改变成绩进行了测试 - 但get_letter_grade(分数)为每个学生返回“A”。我试着对允许的数字范围进行更具体的描述(见下文),但我仍然有同样的问题。

lloyd = { 
     "name": "Lloyd", 
     "homework": [90.0, 97.0, 75.0, 92.0], 
     "quizzes": [88.0, 40.0, 94.0], 
     "tests": [75.0, 90.0] 
    } 
alice = { 
     "name": "Alice", 
     "homework": [100.0, 92.0, 98.0, 100.0], 
     "quizzes": [82.0, 83.0, 91.0], 
     "tests": [89.0, 97.0] 
    } 
tyler = { 
     "name": "Tyler", 
     "homework": [0.0, 87.0, 75.0, 22.0], 
     "quizzes": [0.0, 75.0, 78.0], 
     "tests": [100.0, 100.0] 
    } 

def average(numbers): 
     total = sum(numbers) 
     total = float(total)/len(numbers) 
     return total 

def get_average(student): 
     homework = average(student["homework"]) 
     quizzes = average(student["quizzes"]) 
     tests = average(student["tests"]) 
     studentaverage = (homework * .1 + quizzes * .3 + tests *.6) 
     return studentaverage 

def get_letter_grade(score): 
    if score >= 90: 
     return "A" 
    elif score >= 80: 
     return "B" 
    elif score >= 70: 
     return "C" 
    elif score >= 60: 
     return "D" 
    else: 
     return "F" 

我也试图改变get_letter_grade(分数)的作用有点,使其更加具体的/受限制的(我可能会想走错了路,我很新在这),如下:

def get_letter_grade(score): 
     if score >= 90: 
      return "A" 
     elif score >= 80 and score < 90: 
      return "B" 
     elif score >= 70 and score < 80: 
      return "C" 
     elif score >= 60 and score < 70: 
      return "D" 
     else: 
      return "F" 

但如上所述,我有同样的问题:无论我如何改变他们的成绩,它都会为每个学生返回“A”。

任何意见,见解,智慧等你关心分享将非常感激!

谢谢!

+0

你在哪里使用'get_letter_score'功能? – rassar

回答

0

我试过上面的代码,它没有任何改变就能很好地工作。 也许如果你可以分享你调用函数的方式,我可以对你可能一直遵循的错误程序进行阐述。下面是代码片段及其相应的输出。

lloyd = { 
     "name": "Lloyd", 
     "homework": [90.0, 97.0, 75.0, 92.0], 
     "quizzes": [88.0, 40.0, 94.0], 
     "tests": [75.0, 90.0] 
    } 
alice = { 
     "name": "Alice", 
     "homework": [100.0, 92.0, 98.0, 100.0], 
     "quizzes": [82.0, 83.0, 91.0], 
     "tests": [89.0, 97.0] 
    } 
tyler = { 
     "name": "Tyler", 
     "homework": [0.0, 87.0, 75.0, 22.0], 
     "quizzes": [0.0, 75.0, 78.0], 
     "tests": [100.0, 100.0] 
    } 

def average(numbers): 
     total = sum(numbers) 
     total = float(total)/len(numbers) 
     return total 

def get_average(student): 
     homework = average(student["homework"]) 
     quizzes = average(student["quizzes"]) 
     tests = average(student["tests"]) 
     studentaverage = (homework * .1 + quizzes * .3 + tests *.6) 
     return studentaverage 

def get_letter_grade(score): 
    if score >= 90: 
     return "A" 
    elif score >= 80: 
     return "B" 
    elif score >= 70: 
     return "C" 
    elif score >= 60: 
     return "D" 
    else: 
     return "F" 

# To calculate the grades of each student 
grade_tyler = get_letter_grade(get_average(tyler)) 
grade_lloyd = get_letter_grade(get_average(lloyd)) 
grade_alice = get_letter_grade(get_average(alice)) 

print(grade_lloyd) 
print(grade_alice) 
print(grade_tyler) 

输出:

Ç

另外我还试图单独地调用方法并如预期的结果。

grade_A = get_letter_grade(95) 
grade_B = get_letter_grade(85) 
grade_C = get_letter_grade(75) 
grade_D = get_letter_grade(65) 

print(grade_A) 
print(grade_B) 
print(grade_C) 
print(grade_D) 

输出:

Ç

d