遗憾的TITLE访问NG-模型NG-重复
所以,让我解释一下你我的情况
- 首先有一个父
ng-repeat
- 里面父
ng-repeat
我有3选择选项,这也是加载由ng-repeat
问题我面临的是,我想访问01每个选择选项的,并对更改执行特定操作。我试着设置ng-model
但din't真正行之有效
任何建议表示赞赏,真是花了很多时间在这
<!DOCTYPE html>
<html lang="en-US">
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.4/angular.min.js"></script>
<body>
<style>
.box {border:2px solid #0094ff;}
.box h2 {background:#0094ff;color:white;padding:10px;}
.box p {color:#333;padding:10px;}
.box {
-moz-border-radius-topright:5px;
-moz-border-radius-topleft:5px;
-webkit-border-top-right-radius:5px;
-webkit-border-top-left-radius:5px;
}
</style>
<div ng-app="myApp" ng-controller="myCtrl">
\t <div class="box" ng-repeat="item in propertyData track by $index">
\t <h2>{{item.propertyName}}</h2>
\t <p>
\t <label>Type of Riks {{$index}}</label>
\t <select ng-model="a.modelRiskType" ng-change="riskTypeChange(riskType)">
\t <option ng-repeat="singleItem in item.riskTypeData">{{singleItem.riskType}}</option>
\t </select>
\t <label>Type of damage {{$index}}</label>
\t <select ng-model="b.modelDamageType">
\t <option ng-repeat="singleItem in item.damageData">{{singleItem.damage}}</option>
\t </select>
\t <label>Type of Injury {{$index}}</label>
\t <select ng-model="injury">
\t <option ng-repeat="singleItem in item.injuryData">{{singleItem.injury}}</option>
\t </select>
\t </p>
\t </div>
\t
</div>
</body>
<script>
var app = angular.module('myApp', []);
app.controller('myCtrl', function($scope) {
$scope.propertyData = [
{propertyName:'Header Data1',id:1},
{propertyName:'Header Data2',id:2},
{propertyName:'Header Data3',id:3},
{propertyName:'Header Data4',id:4},
];
$scope.riskTypeData = [
{riskType:'movable',id:1},
{riskType:'Immovable',id:2},
{riskType:'NA',id:3},
];
$scope.damageData = [ \t \t
{damage:'Own Damage',id:4},
{damage:'Own Bodily Damage ',id:5},
{damage:'Fire',id:6},
\t \t {damage:'NA',id:6},
];
$scope.injuryData = [ \t \t
{injury:'Medical Expenses',id:4},
{injury:'Critical Illness',id:5},
{injury:'Death',id:6},
\t \t {injury:'NA',id:6},
];
$scope.modelRiskType = $scope.riskTypeData;
$scope.modelDamageType = $scope.damageData;
for(var i=0;i< $scope.propertyData.length;i++){
\t $scope.propertyData[i]["riskTypeData"] = $scope.riskTypeData
\t $scope.propertyData[i]["damageData"] = $scope.damageData
\t $scope.propertyData[i]["injuryData"] = $scope.injuryData
}
console.log($scope.modelDamageType);
$scope.riskTypeChange = function(data){
$scope.b.modelDamageType.push($scope.damageData[0])
}
});
</script>
</html>
这个问题可以通过遵循“最佳实践”总是有一个'。'来轻松避免。在你的ng模型中。 – georgeawg
@georgeawg你可以请解释一下,因为我是新来的angularjs –
解释“工作不好”。描述问题行为和期望的行为。还包括'riskTypeChange'函数的代码。 – georgeawg