Loopback如何查询基于“hasManyThrough”关系的相关模型？

Question

假设通过使用StrongLoop医生和patiens的标准的例子（https://docs.strongloop.com/display/public/LB/HasManyThrough+relations）：

公共/模型/ physician.json

{ 
    "name": "Physician", 
    "base": "PersistedModel", 
    "properties": { 
    "name": { 
     "type": "string" 
    } 
    }, 
    "validations": [], 
    "relations": { 
    "patients": { 
     "type": "hasMany", 
     "model": "Patient", 
     "foreignKey": "patientId", 
     "through": "Appointment" 
    }, 

公共/模型/ patient.json

{ 
    "name": "Patient", 
    "base": "PersistedModel", 
    "properties": { 
    "name": { 
     "type": "string" 
    } 
    }, 
    "validations": [], 
    "relations": { 
    "physicans": { 
     "type": "hasMany", 
     "model": "Physician", 
     "foreignKey": "physicianId", 
     "through": "Appointment" 
    }, 

共同/models/appointment.json

{ 
    "name": "Appointment", 
    "base": "PersistedModel", 
    "properties": { 
    "appointmentDate": { 
     "type": "date" 
    } 
    }, 
    "validations": [], 
    "relations": { 
    "physician": { 
     "type": "belongsTo", 
     "model": "Physician", 
     "foreignKey": "physicianId" 
    }, 
    "patient": { 
     "type": "belongsTo", 
     "model": "Patient", 
     "foreignKey": "patientId" 
    }, 

让supouse比一位医生可以有0,1,2或更多患者。 这样：

PhysicianId | PatientId 
1----------------1 
1----------------2 
2----------------3 
2----------------4 
3----------------3 
3----------------5 

我怎样才能让所有的医生比拥有相同的病人？

例如：

获取所有的医生比有patientId 3的患者？

在这种情况下其结果必然是：PhysicianId 2和3

Answer 1

GET /patients/{id}/physicians 

参见methods added to the model。