我注意到，在我到XML转换从JSON，如果我的JSON对象之一为null，对象是从XML缺席，例如空属性都将被丢弃/与JSONIX
JSON
{ "name": { "namespaceURI": "", "localPart": "myApp", "prefix": "", "key": "myApp", "string": "myApp" }, "value": { "TYPE_NAME": "generated.MyApp", "inputData": [{ "TYPE_NAME": "generated.MyApp.InputData", "dataType": "text", "mandatory": false, "length": 25, "valid": true, "value":null }] } }
转换为XML输出（marshalString）
var context2 = new j.Context([generated2]); var marshaller2 = context2.createMarshaller(); var objectAsXMLString2 = marshaller2.marshalString(template2);
<myApp> <inputData> <dataType>text</dataType> <mandatory>false</mandatory> <length>25</length> <valid>true</valid> </inputData> </myApp>
话又说回来转换回JSON（unmarshalString）
var unmarshaller2 = context2.createUnmarshaller(); var resultJSON2 = unmarshaller2.unmarshalString(objectAsXMLString2);
{ "name": { "namespaceURI": "", "localPart": "myApp", "prefix": "", "key": "myApp", "string": "myApp" }, "value": { "TYPE_NAME": "generated.MyApp", "inputData": [{ "TYPE_NAME": "generated.MyApp.InputData", "dataType": "text", "mandatory": false, "length": 25, "valid": true }] } }
所以你看，有信息丢失。当发生完整的转换周期时，JSON - > XML - >返回到JSON，一些属性不会被保留。任何null值都会被删除 - 在这种情况下，它是属性的“值”。对于期望某个对象上存在某些属性的下游应用程序，这是一个问题。这是用于生成jsonix映射对象
我的XML模式看起来像这样
<xs:schema attributeFormDefault="unqualified" elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xs:element name="myApp"> <xs:complexType> <xs:sequence> <xs:element name="inputData" maxOccurs="unbounded" minOccurs="0"> <xs:complexType> <xs:sequence > <xs:element type="xs:string" name="dataType"/> <xs:element type="xs:boolean" name="mandatory"/> <xs:element type="xs:short" name="length"/> <xs:element type="xs:string" name="elementId"/> <xs:element type="xs:string" name="formId"/> <xs:element type="xs:anySimpleType" name="value" /> <xs:element type="xs:boolean" name="valid"/> <xs:element type="xs:short" name="precision"/> <xs:element type="xs:short" name="scale"/> </xs:sequence> </xs:complexType> </xs:element> </xs:sequence> </xs:complexType> </xs:element> </xs:schema>
而生成的映射使用jsonix-架构编译器
var generated_Module_Factory = function() { var generated = { name: 'generated', typeInfos: [{ localName: 'MyApp', typeName: null, propertyInfos: [{ name: 'inputData', minOccurs: 0, collection: true, elementName: { localPart: 'inputData' }, typeInfo: '.MyApp.InputData' }] }, { localName: 'MyApp.InputData', typeName: null, propertyInfos: [{ name: 'dataType', required: true, elementName: { localPart: 'dataType' } }, { name: 'mandatory', required: true, elementName: { localPart: 'mandatory' }, typeInfo: 'Boolean' }, { name: 'length', required: true, elementName: { localPart: 'length' }, typeInfo: 'Short' }, { name: 'elementId', required: true, elementName: { localPart: 'elementId' } }, { name: 'formId', required: true, elementName: { localPart: 'formId' } }, { name: 'value', required: true, elementName: { localPart: 'value' }, typeInfo: 'AnySimpleType' }, { name: 'valid', required: true, elementName: { localPart: 'valid' }, typeInfo: 'Boolean' }, { name: 'precision', required: true, elementName: { localPart: 'precision' }, typeInfo: 'Short' }, { name: 'scale', required: true, elementName: { localPart: 'scale' }, typeInfo: 'Short' }] }], elementInfos: [{ typeInfo: '.MyApp', elementName: { localPart: 'myApp' } }] }; return { generated: generated }; }; if (typeof define === 'function' && define.amd) { define([], generated_Module_Factory); } else { var generated_Module = generated_Module_Factory(); if (typeof module !== 'undefined' && module.exports) { module.exports.generated = generated_Module.generated; } else { var generated = generated_Module.generated; } }
是否有在转换期间保留所有属性的方法，即使它们为空？