如何将“排序”程序的输出从子项重定向到父项

Question

我想要做的是使用pipe1从父项到子项发送随机数。然后子进程exec sort程序将这些数字排序并使用pipe2发送回父进程。现在我可以从stdout中得到正确的排序结果，如果我注释掉“if（pipe2In> = 0）{dup2（pipe2In，1）; close（pipe2In）;}”但我无法从父项中的pipe2中读取它们，如下所示。实际上，读取的调用不能返回。我错过了什么吗？感谢任何帮助。

const int READ = 0, WRITE = 1; 
{ 
pid_t pid; 
int pipe1[2], pipe2[2]; 

if (pipe(pipe1)) 
{ 
    cerr << "Error! Pipe 1 Failed. errno = "<< errno << endl; 
    exit(1); 
} 

int pipe1In = pipe1[WRITE]; 
int pipe1Out = pipe1[READ]; 

if (pipe(pipe2)) 
{ 
    cerr << "Error! Pipe 2 Failed. errno = "<< errno << endl; 
    exit(1); 
} 
int pipe2In = pipe2[WRITE]; 
int pipe2Out = pipe2[READ]; 

pid = fork(); 
if(pid < 0) 
{ 
    cerr << "Error! Fork Failed!\n"; 
    exit(1); 
} 
else if (pid == 0) // child 
{ 
    close(pipe1In); 
    close(pipe2Out); 

    if(pipe1Out >= 0) 
    { 
     dup2(pipe1Out, 0); 
     close(pipe1Out); 
    } 
    if(pipe2In >= 0) 
     { 
      dup2(pipe2In, 1); 
     close(pipe2In); 
    } 

    execlp("sort", "sort", "-nr", (char *)NULL); 
    cerr << "Error - Exec Failed!\n"; 
    exit(-2); 
} // end of child 


close(pipe1Out);   // parent continues from here 
close(pipe2In); 

// generate random numbers 
int rn, tem, i, len; 
for (i = 0; i < nWks; i++) 
{ 
    rn = rand(); 
    tem = rn; 
    len = 1; 
    while (tem /= 10) len++; 
    char *bufWrite = (char *) malloc(len+1); 
     sprintf(bufWrite, "%d\n", rn); 
    write(pipe1In, bufWrite, len+1); 
} 
char bufRead[1024]; 
int n; 
while (n = read(pipe2Out, bufRead, sizeof(bufRead)) != 0) 
{ 
    printf("read count %d\n", n); 
} 
} 

Answer 1

sort，直到它在它的输入流接收EOF不给任何输出。为了触发这种情况，在你的父进程中，你应该在读循环之前使用close(pipe1In);。