PHP错误：没有选择数据库

Question

我有一个小的简单的PHP脚本来存储一些值到MYSQL数据库，但我得到没有数据库选择错误。我真的不知道错误在哪里。一些帮助将不胜感激。

下面是脚本：

<?php 

echo "connection receiving"; 
$value0=$_GET['value0']; 


$opendb=mysql_connect("localhost","root","") or die(mysql_error()); 
$db = mysql_select_db('arduino',$opendb); 

if ($opendb){ 
    echo " database open."; 
    if (!$db) { 
    echo mysql_error(); 
    } 
    $query = "INSERT INTO analoog0 VALUES(curdate(), curtime(), '$value0');"; 
    /* Run the query */ 
    $result= mysql_query($query)or die(mysql_error()); 
    mysql_close($opendb); 
    echo "values written = $value0"; 
} 


?> 

当我运行/write.php?value0=25我得到未知数据库 'Arduino的' 无数据库选择

Answer 1

试试这个：

$con = mysqli_connect("localhost", "root", ""); 

// check connection 
if (mysqli_connect_errno()) { 
    echo "Failed to connect to MySQL: " . mysqli_connect_error(); 
} 

$value0 = $_GET['value0']; 
mysqli_query($con, "INSERT INTO arduino.analoog0 VALUES(curdate(), curtime(), '" . $value0 . "')"); 
echo "values written = " . $value0; 
mysqli_close($con);