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我必须使用2肥皂呼叫网址是在一个类中使用。 我的代码是:2肥皂呼叫是使用相同的类
public class Orderinfo extends Activity {
private static final String SOAP_ACTION = "http://xcart.com/data";
private static final String METHOD_NAME = "data";
private static final String NAMESPACE = "http://xcart.com";
private static final String URL = "http://192.168.1.168:8085/XcartLogin/services/RetailerWs?wsdl";
private static final String URL1 = "http://192.168.1.168:8085/XcartLogin/services/TodayC?wsdl";
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.table);
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.setOutputSoapObject(request);
HttpTransportSE ht = new HttpTransportSE(URL);
try {
ht.call(SOAP_ACTION, envelope);
SoapPrimitive response = (SoapPrimitive)envelope.getResponse();
SoapPrimitive s = response;
String str = s.toString();
String resultArr[] = str.split("&");//Result string will split & store in an array
TextView tv = (TextView) findViewById(R.id.textView44);
// TextView tv = new TextView(this);
for(int i = 0; i<resultArr.length;i++){
tv.append(resultArr[i]+"\n\n");
}
} catch (Exception e) {
e.printStackTrace();
}
HttpTransportSE ht1 = new HttpTransportSE(URL1);
try {
ht.call(SOAP_ACTION, envelope);
SoapPrimitive response = (SoapPrimitive)envelope.getResponse();
SoapPrimitive s = response;
String str = s.toString();
String resultArr[] = str.split("&");//Result string will split & store in an array
TextView tv = (TextView) findViewById(R.id.textView43);
// TextView tv = new TextView(this);
for(int i = 0; i<resultArr.length;i++){
tv.append(resultArr[i]+"\n\n");
}
} catch (Exception e) {
e.printStackTrace();
}
}
}
这里不得不首先显示SOAP调用输出为3,第二SOAP调用输出2.but两者都显示2 only.why什么异常here.please帮助我。
雅的正确... thanks..thanks乌拉圭回合的帮助...... DIS是基本mistake..i已经从你那里学到了基本的信息。谢谢你,我得到了我的输出。 – user1570318 2012-08-02 07:13:18