动态嵌套XElements

Question

我想创建一个XML，这将包括一些如下： -

<?xml version="1.0" encoding="utf-8"?> 
<Groups> 
    <Group> 
     <Id>1</Id> 
     <GroupName>Group1</CategoryId> 
     <Products> 
      <Product> 
       <ProductId>1</ProductId> 
       <ProductName>Apples</ProductName> 
      </Product> 
      <Product> 
       <ProductId>2</ProductId> 
       <ProductName>Oranges</ProductName> 
      </Product> 
      <Product> 
       <ProductId>3</ProductId> 
       <ProductName>Lemons</ProductName> 
      </Product> 
     </Products> 
     <DateCreated></DateCreated> 
     <DateModified></DateModified> 
    </Group> 
    <Group> 
     <Id>2</Id> 
     <GroupName>Group2</CategoryId> 
     <Products> 
      <Product> 
       <ProductId>3</ProductId> 
       <ProductName>Grapes</ProductName> 
      </Product> 
      <Product> 
       <ProductId>4</ProductId> 
       <ProductName>PineApple</ProductName> 
      </Product> 
     </Products> 
     <DateCreated></DateCreated> 
     <DateModified></DateModified> 
    </Group> 
</Groups> 

你可以从我的例子中看到的，Product量可以从1组改变到另一个。

我该如何创建一个动态XML并且能够在以后读取相同的XML。

目前我的代码来创建XML如下：

internal XElement ConstructGroupXML(int numberOfItems) 
{ 
    XElement xmlList = new XElement("Groups", 
     from a in dataModel.CreateGroupList(numberOfItems) 
     select new XElement("Group", 
      new XElement("Id", a.Id), 
      new XElement("GroupName", a.GroupName), 
      new XElement("Products", 
       new XElement("ProductId", a.Products[i].Id), 
       new XElement("ProductName", a.Products[i].ProductName), 
       new XElement("CategoryId", a.Products[i].Category.Id), 
       new XElement("CategoryName", a.Products[i].Category.CategoryName), 
       new XElement("SubCategoryId", a.Products[i].SubCategory.Id), 
       new XElement("SubCategoryName", a.Products[i].SubCategory.SubCategoryName), 
      new XElement("DateCreated", a.DateCreated), 
      new XElement("DateModified", a.DateModified) 
     ) 
    ); 

    return xmlList; 
} 

的CreateGroupList方法返回与组和嵌入这些组的产品名单的对象，所以每个组我想循环在产品列表中并生成XML。

Answer 1

好，我设法找到解决办法：

from o in a.Products 
select new XElement("Products", 
    new XAttribute("ProductId", o.Id), 
    new XElement("ProductName", o.ProductName), 
    new XElement("CategoryId", o.Category.Id), 
    new XElement("CategoryName", o.Category.CategoryName), 
    new XElement("SubCategoryId", o.SubCategory.Id), 
    new XElement("SubCategoryName", o.SubCategory.SubCategoryName), 

现在我只需要找出如何阅读本XML